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4 years ago

What would make bromine , a group 17 element, more similar to a noble gas?

1 answer:

8 0

It is more similar to a noble gas because noble gases are the group 18 elements. Noble gases are gases which have their outer shell complete and so cannot give out or gain any more electrons. And cannot react with other elements. Hope i helped.

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An acetal polymer block is fixed to the rigid plates at its top and bottom surfaces. If the top plate displaces 2 mm horizontall

Taya2010 [7]

Answer:

The shear modulus of the polymer is 5 MPa

Solution:

As per the question:

displacement of the top plate, d = 2 mm = 0.002 m

Horizontal Force, P = 2 kN = 2000 N

Width of the block, w = 100 mm = 0.1 m

By small angle analysis:

Angle, $\gamma = \frac{2}{200} = 0.01 rad$

Now,

Stress, $\tau$ = $\frac{P}{Area} = \frac{2000}{0.4\times 0.1} = 50000 Pa$

$G = \frac{\tau}{\gamma} = \frac{50000}{0.01} = 5 MPa$

3 0

3 years ago

A. Water has many unique properties. Identify a property of water and explain why this property makes water vital to living orga

rosijanka [135]

a) It can dissolve other substances and has high specific heat capacity.

b) Pressure is transferred equally in all directions

c) F=14*0.04/0.02=28 N

d) I'd expect that it will sink cause weight will pull it to the bottom

e) Because the buoyant force is stipulated by difference between pressures in the top and bottom surfaces of a body.

f) Because this force increases in denser liquids: $F_b=\rho gV$ , where rho is density.

g) Q=Av, where v - speed, A - area. With the same flow rate v=Q/A, so larger area decreases speed and vice versa.

8 0

3 years ago

A spherical mirror gives an image magnified 5 times at a distance 5 m. determine whether the mirror is convex or concave? How mu

irakobra [83]

Answer:

1. Concave mirror.

2. 4.17 m or 417 cm.

Explanation:

The following data were obtained from the question:

Object distance (u) = 5 m

Magnification (M) = 5

Focal length (f) =..?

1. Identification of the mirror.

To determine whether or not the mirror is concave or convex, we must first of all calculate the image distance.

This can be obtained as follow:

Object distance (u) = 5 m

Magnification (M) = 5

Image distance (v) =.?

Magnification (M) = image distance (v) /object distance (u).

M = v/u

5 = v/5

Cross multiply

v = 5 x 5

v = 25 m

Since the image distance obtained is positive, the mirror is said to be a concave mirror.

2. Determination of the focal length of the mirro.

This can be obtained as follow:

Object distance (u) = 5 m

Image distance (v) = 25 m

Focal length (f) =...?

1/f = 1/v + 1/u

1/f = 1/25 + 1/5

1/f = 0.04 + 0.2

1/f = 0.24

Cross multiply

f x 0.24 = 1

Divide both side by 0.24

f = 1/0.24

f = 4.17 m

Converting the focal length of cm, we have:

1 m = 100 cm

Therefore, 4.17 m = 4.17 x 100 = 417 cm

Therefore, the focal length of the mirror is 4.17 or 417 cm.

4 0

3 years ago

A particular star is white. Another star that is much hotter is expected to be ______.

jenyasd209 [6]

Blue

hope this helps :)

4 0

4 years ago

Read 2 more answers

Classify each of the following as a physical or chemical property of

notka56 [123]

A) physical.
b) chemical
c) physical.
d) physical.
e) physical.

7 0

3 years ago