Ask question

Ask question

All categories

3 years ago

13

Set of the equation X+9=26

1 answer:

trapecia [35]3 years ago

8 0

Answer:

17

Step-by-step explanation:

subtract 9 from 26 and you should get the answer

You might be interested in

Pie

Answer:

I

1)-574 2)-874 3)-902 4)No answer bz have two dismal place

8 0

2 years ago

A football team gained 9 yards on one play and then lost 22 yards on the next.Write a sum of integers to find theoverral change

anastassius [24]

Answer:

-13 yards

Step-by-step explanation:

Estimating that we start off on the middle line, we could solve this by simply looking at a number line. Moving 9 yards ahead would put us at 9. But moving back 22 would place us at a negative number. An easy way of doing this is subtracting 9 from 22:

22 - 9 = 13

But, we already know that since the answer is to the left of zero, it will be a negative number. So we flip the sign to get -13 yards.

3 0

3 years ago

1. At a leather shop, 50 leather jackets were sold in February. The shop keeper at the store wants to encourage the sales team t

podryga [215]

Answer:

65 shirts.

Step-by-step explanation:

50 is the amount of shirts sold in February.

30% increase=1.3

1.3(50)

65

They need to sell 65 shirts in March to get the bonus.

5 0

3 years ago

The place value of the 3 in 27.4359 is _____.

melisa1 [442]

In the hundreds place so its 300

8 0

3 years ago

Read 2 more answers

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

8 0

2 years ago