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Pavlova-9 [17]
3 years ago
11

What type of circuit is illustrated?

Chemistry
2 answers:
Ber [7]3 years ago
5 0
I believe it's B: series circuit



good luck
ycow [4]3 years ago
3 0

Answer : the correct option is, (b) series circuit

Explanation :

Parallel circuit : In this circuit, the potential across each of the components are same but the current flow in the circuit is equal to the sum of the current flow of each components.

Series circuit : In this circuit, the current flow each of the components are same but the potential across the circuit is equal to the sum of the potential of each components.

Open circuit : In this circuit, there will be no current flow that means the wires are cut off but in this circuit there will be some voltage.

Short circuit : When the live wire comes in the contact with the neutral wire, the short, this is the condition of the short circuit.

Hence, the given circuit is a type of of series circuit.

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f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
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Answer:

Explanation:

H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

mole of NaOH = 23.6 * 10 ⁻³L * 0.2M

= 0.00472mole

let x be the no of mole of H3PO4 required of  0.00472mole of NaOH

3 mole of NaOH required ------- 1 mole of H3PO4

0.00472mole of NaOH ----------x

cross multiply

3x = 0.0472

x = 0.00157mole

[H3PO4] = mole of H3PO4 / Vol. of H3PO4

= 0.00157mole / (10*10⁻³l)

= 0.157M

<h3>The concentration of unknown phosphoric acid is  0.157M</h3>
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