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In-s [12.5K]
2 years ago
9

A student decreases the temperature of a 417 cm³ balloon from 278 K to 231 K. Assuming constant pressure, what should the new vo

lume of the balloon be?
376 cm³
417 cm³
462 cm³
924 cm³
Chemistry
1 answer:
Natali5045456 [20]2 years ago
4 0

Answer:

C

Explanation:

Charles law states that volume of gas is directly proportional to temperature at constant pressure

V/T = k

where V - volume , T - temperature and k - constant

\frac{V1}{T1} = \frac{V2}{T2}

T1

V1

=

T2

V2

where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation

in the question it states that the temperature has been increased from 278 K to 231 K but it should actually be temperature is decreased from 278 K to 308 K

substituting the values in the equation

\frac{417cm^{3} }{278K} = \frac{V}{308 K}

278K

417cm

3

=

308K

V

V = 462 cm³

the answer should be C. 462 cm³

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