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Ainat [17]
3 years ago
9

5 is one-fourth the number t

Mathematics
1 answer:
never [62]3 years ago
3 0
So... T = 1.25?, if this isn't correct ask the question again.. i don't fully get it
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I need help again brainiest who ever get this right
Leona [35]

Answer:

Step-by-step explanation:

26x25x24x23x22x21x10x9=30,891,577,600

=Thirty billion, eight hundred ninety-one million, five hundred seventy-seven thousand, six hundred.

the answer was kind of in the question btw :)

6 0
3 years ago
How can i estimate a number from a bar graph??
olga55 [171]
You should first find out what lines are what,
Like for example, If you had 5 - 10 - 15 as the Y Lines and the bar was between 5 and 10 then your best bet would be to estimate what the middle of 5 and 10 is which would be 7 or 8.
8 0
3 years ago
Based on experience, the Ball Corporation’s aluminum can manufacturing facility in Ft. Atkinson, Wisconsin, knows that the metal
Veronika [31]

Answer:

a) 3.128

b) Yes, it is an outerlier

Step-by-step explanation:

The standardized z-score for a particular sample can be determined via the following expression:

z_i = {x_i -\bar x}/{s}

Where;

\bar x = sample means

s = sample standard deviation

Given data:

the mean shipment thickness (\bar x) = 0.2731 mm

With the standardized deviation (s) = 0.000959 mm

The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression

z_i = {x_i -\bar x}/{s}

z_i = {0.2761-0.2731}/{ 0.000959}

z_i = 3.128

b)

From the standardized z-score

If [z_i < 2]; it typically implies that the data is unusual

If [z_i > 2]; it means that the data value is an outerlier

However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.

6 0
3 years ago
At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
pav-90 [236]

Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
3 years ago
The price of a math book is $50 but you only have $35 with you. If you get a discount of 20% how much money do you need to borro
geniusboy [140]
$5 because you do 50 times 20% (get 10) subtract 10 from 50 (50-10). You’d get $40! You have $35 so therefore, $40-$35=$5!
6 0
3 years ago
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