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GenaCL600 [577]
3 years ago
15

The pitch made by a musical instrument is dependent on the frequency of the wave. Frequency is the inverse of period. What impac

t do you think the frequency of a wave has on the wave speed?
Physics
2 answers:
Blizzard [7]3 years ago
4 0

I think the frequency of the wave has <em>no effect</em> whatsoever on the wave speed.  The speed of a wave completely depends on the characteristics of the medium it's traveling through.  

Physical properties of the medium determine the speed of mechanical waves, like sound, ocean waves, seismic waves, Slinky waves etc.  If it depended on the frequency of the waves, then the sound of the band or orchestra would be all smeared out when it reaches you ... you'd hear the drums and bass first, and the flutes and trumpets last.

Electrical properties of the medium determine the speed of electromagnetic waves, like radio, light, and X-rays. If it depended on the frequency of the waves, then you couldn't watch a football game in the stadium or on TV.  The reds, oranges, and yellows would reach your eyes first, and then the greens, blues, and violets would arrive later.  The action would be all smeared out, and things that happened first might reach  your eyes last.  What a mess !

polet [3.4K]3 years ago
4 0

Answer:

it has no affect at all .. doesnt change

Explanation:

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<span>An object is acted upon by a force of 22 newtons to the right and a force of 13 newtons to the left.

(1)  22 N to the right
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3 years ago
A tree performing photosynthesis is an example of _____________
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3 years ago
What is the force on a 1000kg elevator that is falling freely at 9.8 m/sec^2
Advocard [28]
From Newton's second law, we know F = ma, where a is the acceleration and m is the mass in kg.

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3 years ago
A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net = 4.444 N
Dmitriy789 [7]

Answer:

The value of third charge is 0.8μC.

Explanation:

Given that.

Magnitude of net force=4.444 N

According to figure,

Suppose, First charge = 2.4 μC

Second charge = 6.2 μC

Distance r₁ = 9.8 cm

Distance r₂ = 2.1 cm

We need to calculate the value of r

Using Pythagorean theorem

r=\sqrt{(r_{1})^2+(r_{2})^2}

Put the value into the formula

r=\sqrt{(9.8)^2+(2.1)^2}

r=10.02\ cm

We need to calculate the force

Using formula of force

F_{12}=\dfrac{kq_{1}q_{2}}{(r)^2}

Force F₁₂,

F_{12}=\dfrac{9\times10^{9}\times2.4\times10^{-6}\times6.2\times10^{-6}}{(10.02\times10^{-2})^2}

F_{12}=13.33\ N

F_{21}=-13.33\ N

Force F₂₃,

F_{23}=\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(10.02)^2}

We need to calculate the value of third charge

F_{net}=F_{21}+F_{23}

4.444=-13.33+\dfrac{9\times10^{9}\times6.2\times10^{-6}\times q_{3}}{(5.01)^2}

q_{3}=\dfrac{(4.444+13.33)\times(5.01\times10^{-2})^2}{9\times10^{9}\times6.2\times10^{-6}}

q_{3}=7.99\times10^{-7}\ C

q_{3}=0.8\times10^{-6}\ C

Hence, The value of third charge is 0.8μC.

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