Question

Light travels from crown glass (n=1:52) into air (n=1.00). The angle of refraction in

Answer 1

The angle of incidence in glass is $34.7^{\circ}$

Explanation:

We can solve this problem by applying Snell's law of refraction, which states that:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

$n_1, n_2$ are the index of refraction of the first and second medium, respectively

$\theta_1, \theta_2$ are the angle of incidence and refraction, respectively

In this problem we have:

$n_1 = 1.52$ is the index of refraction of the first medium (glass)

$n_2 = 1.00$ is the index of refraction of the second medium (air)

$\theta_2 =60^{\circ}$ is the angle of refraction in glass

Solving for $\theta_i$, we find the angle of incidence:

$\theta_1 = sin^{-1} (\frac{n_2 sin \theta_2}{n_1})=\sin^{-1}(\frac{(1.00)(sin 60^{\circ})}{1.52})=34.7^{\circ}$

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