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jonny [76]
2 years ago
12

Que es el potencial motor?

Physics
1 answer:
aleksandrvk [35]2 years ago
5 0

Explanation:

Motor evoked potentials (MEPs) are the electrical signals recorded from the descending motor pathways or from muscles following stimulation of motor pathways within the brain.

Espero eso ayude. Marque como más inteligente.

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The electric potential difference across the membrane of a body cell is 0.070 V (higher on the outside than on the inside). The
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Answer:

The electric field is 8.75 \times 10^{6}~v~m^{-1} and the ditection is from outer to inner side of the membrane.

Explanation:

We know the electric field (\vec{E}) is given by \vec{E} = - \nabla V, 'V' being the potential.

In 1-D, it can be written as

E=\dfrac{V}{d}

where 'd' is the separation of space in between the potential difference is created.

Given, V = 0.070~V~ and the thickness of the cell membrane is d = 8.0 \times 10^{-9}~m.

Therefore the created electric field through the cell membrane is

E = \dfrac{0.07~V}{8 \times 10^{-9}~m} = 8.75 \times 10^{6}~m~s^{-1}

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A beryllium-9 ion has a positive charge that is double the charge of a proton, and a mass of 1.50 ✕ 10−26 kg. At a particular in
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Answer:

Magnetic force, F = 3.52\times 10^{-13}\ N

Explanation:

Given that,

A beryllium-9 ion has a positive charge that is double the charge of a proton, q=2\times 1.6\times 10^{-19}\ C=3.2\times 10^{-19}\ C

Speed of the ion in the magnetic field, v=5\times 10^6\ m/s

Its velocity makes an angle of 61° with the direction of the magnetic field at the ion's location.

The magnitude of the field is 0.220 T.

We need to find the magnitude of the magnetic force on the ion. It is given by :

F=qvB\\\\F=3.2\times 10^{-19}\times 5\times 10^6\times 0.22\\\\F=3.52\times 10^{-13}\ N

So, the magnitude of magnetic force on the ion is 3.52\times 10^{-13}\ N.

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Answer:

sorry I need points

Explanation:

IM SO SORRY

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