1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
djyliett [7]
4 years ago
9

Elaborate on what can be learned about the properties by the location of element on the periodic table. Use atomic number 13 as

an example. A) It is a non-metal, has 3 valence electrons, becomes a cation with a -3 charge, and is brittle, moldable, and non-conductive. B) It is a metalloid, has 3 valence electrons, becomes a cation with a -5 charge, and is workable, inelastic, and non-conductive. C) It is a main group metal, has 3 valence electrons, becomes a cation with a +3 charge, and is ductile, malleable, and conductive. D) It is a transition metal, has 1 valence electrons, becomes a cation with a +1 charge, and is ductile, malleable, and conductive. Eliminate
Physics
2 answers:
svet-max [94.6K]4 years ago
7 0

Answer:

C. It is a main group metal, has 3 valence electrons, becomes a cation with a +3 charge, and is ductile, malleable, and conductive.

Explanation:It is a main group metal, has 3 valence electrons, becomes a cation with a +3 charge, and is ductile, malleable, and conductive.

The location of element on the periodic table gives the electron configuration. From this you know the number of valence electrons, type of ion formed (cation or anion), and the charge of the ion. Additionally the location gives info about the properties because you know if the element is a metal, nonmetal, or metalloid. Using atomic number 13 as an example - Aluminum is a main group metal, has 3 valence electrons, becomes a cation with a +3 charge, and is ductile, malleable, and conductive.

aleksklad [387]4 years ago
4 0

The right answer is c

You might be interested in
acceleration is defined as the rate of change for which characteristic? a. displacement b. position c. velocity d. time
fredd [130]
The answer is velocity.
7 0
4 years ago
ASAP HELP PLZZZZZZZZZZWhich of the following happens when normal force and gravitational force acting on an object are unbalance
wel

Answer:

up and down I think

Explanation:

3 0
3 years ago
Read 2 more answers
if you double the magnitude of a vector, does it follow that the magnitude of the components double? Give example.
jarptica [38.1K]

Answer:

The magnitude of the vector clearly doubles if each of its components is doubled.

Explanation:

8 0
3 years ago
Although 0 dB is often referred to as the lower threshold of human hearing, it is important to realize that the human ear is not
d1i1m1o1n [39]

Answer:

a) 3000 Hz;

b) 30 dB;

c) 1000 times.

Explanation:

a) From the human audiogram given on the figure below the black line represents the threshold for hearing the sound at each frequency. We see that the least intensity is necessary for the frequency of about 3000 Hz.

b) Using the same audiogram we see that we would need the sound of the intensity of about 30dB.

c) The least perceptible sound at 1000 Hz must be 0dB while at 100 Hz it is 30dB. These are logarithmic quantities. To transform them to the linear quantities we use the formula

I(\text{in dB})=10\log\frac{I}{I_0(\text{at }1000\text{ Hz})},

where  I_0(\text{at }1000\text{ Hz}) is the hearing threshold at 1000 Hz.

Therefore we have the following

0\text{ dB}=10\log\frac{I_1}{I_0(\text{at }1000\text{ Hz})}\quad 30\text{ dB}=10\log\frac{I_2}{I_0(\text{at }1000\text{ Hz})}

I_1 is the threshold at 1000Hz and I_2 is the threshold at 100Hz.

By exponentiating we have

10^0=\frac{I_1}{I_0(\text{at }1000\text{ Hz})},\quad 10^3=\frac{I_2}{I_0\text{at }1000\text{ Hz}}.

Now dividing these two equations we get

\frac{I_2}{I_1}=\frac{10^3}{10^0}=1000.

Therefore, the least perceptible sound at 100Hz is 1000 times more intense than the least perceptible sound at 1000Hz.

Note: I got these values unisng the audiogram that is attached here. The one that you have might be slightly different and might yield different answers.

7 0
3 years ago
Q C Ganymede is the largest of Jupiter's moons. Consider a rocket on the surface of Ganymede, at the point farthest from the pla
guapka [62]

The answer is $v=15.6 \mathrm{~km} / \mathrm{s}$.

<h3>What is kinetic energy?</h3>
  • A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
  • Kinetic energy comes in five forms: radiant, thermal, acoustic, electrical, and mechanical.
  • The energy of a body in motion, or kinetic energy (KE), is essentially the energy of all moving objects. Along with potential energy, which is the stored energy present in objects at rest, it is one of the two primary types of energy.
  • Explain that a moving object's mass and speed are two factors that impact the amount of kinetic energy it will possess.

Determine the escape speed for the rocket from the planet-satellite system:

The potential energy of the rocket due to Ganymede when it is on the surface of the Ganymede is,

$$U_1=-\frac{G M_{\mathrm{G}} m}{R_G}$$

The potential energy of the rocket due to Jupiter

when it is on the surface of the Ganymede is,

$$U_2=-\frac{G M_{\mathrm{J}} m}{R}$$

Here, R is a separation between Jupiter and Ganymede.

To escape from the surface of Ganymede potential energy of the rocket due to Jupiter and Ganymede is equal to the kinetic energy of the rocket.

$$\begin{aligned}&\frac{1}{2} m v^2+U_1+U_2=0 \\&\frac{1}{2} m v^2=-U_1-U_2 \\&\frac{1}{2} m v^2=\frac{G M_{\mathrm{G}} m}{R_G}+\frac{G M_{\mathrm{J}} m}{R} \\&\frac{1}{2} v^2=\frac{G M_{\mathrm{G}}}{R_G}+\frac{G M_{\mathrm{J}}}{R}\end{aligned}$$

$v^2=\frac{2 G M_{\mathrm{G}}}{R_G}+\frac{2 G M_{\mathrm{T}}}{R}$

$v=\sqrt{2 G\left(\frac{M_{\mathrm{G}}}{R_G}+\frac{M}{R}\right)}$

$v=\sqrt{2\left(6.67 \times 10^{-11} \mathrm{~N} \cdot \mathrm{m}^2 / \mathrm{kg}^2\right)\left(\frac{1.495 \times 10^{23} \mathrm{~kg}}{2.64 \times 10^6 \mathrm{~m}}+\frac{1.90 \times 10^{27} \mathrm{~kg}}{1.071 \times 10^9 \mathrm{~m}}\right)}$

$v=15.6 \times 10^3 \mathrm{~m} / \mathrm{s}$

$v=15.6 \mathrm{~km} / \mathrm{s}$

To learn more about kinetic energy, refer to:

brainly.com/question/25959744

#SPJ4

3 0
2 years ago
Other questions:
  • Particles in a __________ wave move in an elliptical or circular motion. question 4 options: sound longitudinal transverse surfa
    11·2 answers
  • Radio astronomers detect electromagnetic radiation at 44.0 MHz from an interstellar gas cloud. They suspect this radiation is em
    15·1 answer
  • Baking cake is what a physical or chemical change
    13·1 answer
  • A teacher sends her students on a treasure hunt. She gives the following instructions:
    10·1 answer
  • Which statement best describes scientific laws? (1 point)
    12·1 answer
  • find the angle between two forces of magnitude 27N and 30N if the magnitude of the resultant of the two force is 8N​
    7·1 answer
  • Question 12 (Mandatory) (5 points)
    7·1 answer
  • Which of the following is NOT a type of sediment?
    12·1 answer
  • One one-thousandth is expressed by which prefix?
    13·1 answer
  • a ball is thrown vertically upward with an initial speed of 20 m/s. What is the velocity right before returning to y
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!