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Akimi4 [234]
3 years ago
11

In which type of wave does the medium move parallel to the direction of the energy transport?

Physics
1 answer:
creativ13 [48]3 years ago
7 0
The <span>longitudinal wave. </span>
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Arrange this letters plss lubilsoity​
Blizzard [7]

Answer:

Solubility

Explanation:

found

possible to solve

4 0
3 years ago
A 1500 kg weather rocket accelerates upward at 10m/s2. It explodes 2.0 s after liftoff and breaks into two fragments, one twice
ladessa [460]

Answer:

Approximately \rm 19.8\; m\cdot s^{-1} (downwards.)

Assumptions:

  • the rocket started from rest;
  • the gravitational acceleration is constantly \rm -9.8\; m \cdot s^{-2};
  • there's no air resistance on the rocket and the two fragments.
  • Both fragments traveled without horizontal velocity.

Explanation:

The upward speed of the rocket increases by \rm 10\; m \cdot s^{-1}. If the rocket started from rest, the vertical speed of the rocket should be equal to \rm 20\; m \cdot s^{-1}.

The mass of the rocket (before it exploded) is 1500 kilograms. At 20 m/s, its momentum will be equal to \rm 20 \times 1500 = 30,000\; kg \cdot m\cdot s^{-1}.

What's the initial upward velocity, u, of the lighter fragment?

The upward velocity of the lighter fragment is equal to v = 0 once it reached its maximum height of x = \rm 530\; m.

v^2 - u^2 = 2g \cdot x.

\begin{aligned}u &= \sqrt{v^2 - 2g\cdot x} \\ &= \sqrt{-2 (-9.8) \times 530}\\ &\approx \rm 101.922\; m \cdot s^{-1}\end{aligned}.

Mass of the two fragments:

  • Lighter fragments: \displaystyle \frac{1}{1 + 2} \times 1500 =\rm 500\; kg.
  • Heavier fragment: \displaystyle \frac{2}{1 + 2} \times 1500 =\rm 1000\; kg.

Initial momentum of the lighter fragment:

m \cdot v = \rm 10192.2\; kg \cdot m \cdot s^{-1}.

If there's no air resistance, momentum shall conserve. The momentum of the lighter fragment, plus that of the heavier fragment, should be equal to that of the rocket before it exploded.

The initial momentum of the heavier fragment should thus be equal to the momentum of the two pieces, combined, minus the initial momentum of the lighter fragment.

\rm 30000 - 10192.2 = 19807.8\;kg \cdot m \cdot s^{-1}.

Velocity of the heavier fragment:

\displaystyle \rm \frac{19807.8\;kg \cdot m \cdot s^{-1}}{1000\; kg} \approx 19.8\; m \cdot s^{-1}.

5 0
4 years ago
Read 2 more answers
Read the question below.
Oxana [17]

Answer:

Experimental

Explanation:

Here the dependency of pressure on the temperature is to be determined. For finding this factor we need to calculate the pressure of the object at different temperature.

The process of calculating pressure for different temperature is experimental investigation because we need to perform this experiment for finding these value. On the basis of observed values the we can conclude the dependency.

Thus, this investigation is experimental.

8 0
3 years ago
Read 2 more answers
An electric charge in a magnetic field will experience no force if the charge is moving _______ to the field.
BlackZzzverrR [31]

Answer:

Parallel

Explanation:

An electric charge in a magnetic field will experience no force if the charge is moving parallel to the field.

6 0
3 years ago
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A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t
LekaFEV [45]
Differentiate the expression, to obtain expression for velocity. Set velocity to 0, this when max height is reached. Obtain the tmax from that expression.

<span>h(t) = –16t² + 32t + 6
</span><span>h'(t) = –32t² + 32
0 = </span>–32t² + 32
t max= 1

hmax = <span> –16(1)² + 32(1) + 6
hmax = 22

Therefore, first option is the correct answer.</span>
8 0
3 years ago
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