Explanation:
initial height, yo = 2 m
initial velocity, u = 20 m/s
angle of projection,θ = 5 degree
distance of net = 7 m
height of net = 1 m
Let it covers a vertical distance y in time t .
Use Second equation of motion for vertical motion
As it hits the ground in time t, so put y = 0
Taking positive sign, t = 0.84 s
The ball travels a horizontal distance x in time t
X = 20 Cos5 x t
X = 16.76 m
As this distance is more than the distance of net, so it clears the net.
Let t' be the time taken to travel a horizontal distance equal to the distance of net
7 = 20 cos5 x t'
t' = 0.35 s
Let the vertical distance traveled by the ball in time t' is y'.
So,
y' = 2.008 m
So, it clears the net which is 1 m high.
It clears the net by a vertical distance of 2.008 - 1 = 1.008 m and horizontal distance 16.76 - 7 = 9.76 m
your welcome, and have a great day.
Answer:
Explanation:
Given
Electric Field Strength 
When a charged particle enters the Electric field it Experience a force in the direction of electric field (for positive charge and vice-versa for negative charge)
charge on Electron 
mass of electron 
Force 
acceleration of electron 
<span>One half-life produces (1/2) of the decaying substance.
There would still be 48 atoms. But 24 would have thrown off
particles from their nucleuses, and only 24 would still be radioactive.</span>
False, the hypothesis is before their investigation or experiment
