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Dmitry_Shevchenko [17]

2 years ago

8

Tarik winds a small paper tube uniformly with 185 turns of thin wire to form a solenoid. The tube's diameter is 7.51 mm and its

length is 2.19 cm . What is the inductance, in microhenrys, of Tarik's solenoid

1 answer:

bonufazy [111]2 years ago

7 0

The inductance, in microhenrys, of Tarik's solenoid 196μH.

<h3>What is Solenoid?</h3>

A coil of enameled or insulated wire coiled on a rod-shaped form constructed of solid iron, solid steel, or powdered iron is referred to as a solenoid. These kinds of gadgets can be utilised as miniaturised wireless receiving antennas, inductors in electrical circuits, and as electromagnets.

The inductance (L) of a coil wire (e.g solenoid) is given by;

L = μ₀N²A / l --------------(i)

Where;

l = the length of the solenoid

A = cross-sectional area of the solenoid

N= number of turns of the solenoid

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

From the question;

N = 185 turns

l = 2.19cm = 0.019m

diameter, d = 7.51mm = 0.00751m

But;

A = π d² / 4 [Take π = 3.142 and substitute d = 0.00751m]

A = 3.142 x 0.00751² / 4

A = 4.42 x 10⁻⁵m²

Substitute these values into equation (i) as follows;

L = 4π x 10⁻⁷ x 185² x 4.42 x 10⁻⁵ / 0.0219 [Take π = 3.142]

L = 4(3.142) x 10⁻⁷ x 185² x 4.42 x 10⁻⁵ / 0.0219

L = 196 x 10⁻⁶ H

L = 196 μH

Therefore the inductance in microhenrys of the Tarik's solenoid is 196 μH.

to learn more about Solenoid go to - brainly.com/question/1873362

#SPJ4

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B. A 20kg wagon is pulled up a 30° incline at an acceleration of 2.5ms?. The force pulling the wagon is parallel to the incline

yawa3891 [41]

The value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.

<h3>Coefficient of the kinetic friction</h3>

The value of coefficient of kinetic friction is calculated as follows;

F - Ff = ma

F - μmgcosθ = ma

where;

F is applied force
μ is coefficient of kinetic friction
m is mass of the wagon
a is acceleration of the wagon

182 - μ(20 x 9.8 x cos30) = 20(2.5)

182 - 169.74μ = 50

182 - 50 = 169.74μ

132 = 169.74μ

μ = 132/169.74

μ = 0.78

Thus, the value of the coefficient of kinetic friction between the wagon and inclined surface is 0.78.

Learn more about coefficient of friction here: brainly.com/question/20241845

7 0

3 years ago

A turtle and a rabbit are in a 150 meter race. The rabbit decides to give the turtle a 1 minute head start. The turtle moves at

yan [13]

Answer:

a) $s_{T} = 30\,m$ , b) $t = 5\,min$ , c) $\Delta t = 6.667\,s$ , d) $\Delta s_{R} = 33.333\,m$ , e) $t' = 11.667\,s$ , f) The rabbit won the race.

Explanation:

a) As turtle moves at constant speed, its position is determined by the following formula:

$s_{T} = v_{T}\cdot t$

Where:

$t$ - Time, measured in seconds.

$v_{T}$ - Velocity of the turtle, measured in meters per second.

$s_{T}$ - Position of the turtle, measured in meters.

Then, the position of the turtle when the rabbit starts to run is:

$s_{T} = \left(0.5\,\frac{m}{s} \right)\cdot (60\,s)$

$s_{T} = 30\,m$

The position of the turtle when the rabbit starts to run is 30 meters.

b) The time needed for the turtle to finish the race is:

$t = \frac{s_{T}}{v_{T}}$

$t = \frac{150\,m}{0.5\,\frac{m}{s} }$

$t = 300\,s$

$t = 5\,min$

The time needed for the turtle to finish the race is 5 minutes.

c) As rabbit experiments a constant acceleration until maximum velocity is reached and moves at constant speed afterwards, the time required to reach such speed is:

$v_{R} = v_{o,R} + a_{R}\cdot \Delta t$

Where:

$v_{R}$ - Final velocity of the rabbit, measured in meters per second.

$v_{o,R}$ - Initial velocity of the rabbit, measured in meters per second.

$a_{R}$ - Acceleration of the rabbit, measured in $\frac{m}{s^{2}}$ .

$\Delta t$ - Running time, measured in second.

$\Delta t = \frac{v_{R}-v_{o,R}}{a_{R}}$

$\Delta t = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{1.50\,\frac{m}{s^{2}} }$

$\Delta t = 6.667\,s$

The time taken by the rabbit to reach maximum speed is 6.667 s.

d) On the other hand, the position reached by the rabbit when maximum speed is reached is determined by the following equation of motion:

$v_{R}^{2} = v_{o,R}^{2} + 2\cdot a_{R}\cdot \Delta s_{R}$

$\Delta s_{R} = \frac{v_{R}^{2}-v_{o,R}^{2}}{2\cdot a_{R}}$

$\Delta s_{R} = \frac{v_{R}^{2}-v_{o,R}^{2}}{2\cdot a_{R}}$

Where $\Delta s_{R}$ is the travelled distance of the rabbit from rest to maximum speed.

$\Delta s_{R} = \frac{\left(10\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(1.50\,\frac{m}{s^{2}} \right)}$

$\Delta s_{R} = 33.333\,m$

The distance travelled by the rabbit from rest to maximum speed is 33.333 meters.

e) The time required for the rabbit to finish the race can be determined by the following expression:

$t' = \frac{\Delta s_{R}}{v_{R}}$

$t' = \frac{150\,m-33.333\,m}{10\,\frac{m}{s} }$

$t' = 11.667\,s$

The time required for the rabbit from rest to maximum speed is 11.667 seconds.

f) The animal with the lowest time wins the race. Now, each running time is determined:

Turtle:

$t_{T} = 300\,s$

Rabbit:

$t_{R} = 60\,s + 6.667\,s + 11.667\,s$

$t_{R} = 78.334\,s$

The rabbit won the race as $t_{R} < t_{T}$ .

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4 years ago

What increases the work output of a machine

Ilia_Sergeevich [38]

There are only two things you can do to increase the work output of a machine:

1). Increase the work INput to the machine.

2). Make the machine more efficient ... do things like lubricating it better to eliminate some internal friction.

4 0

4 years ago

assuming that the air temperature is constant, what happens to a hot air balloon if it goes too far up in the atmosphere , where

PIT_PIT [208]

Hello!

The balloon explodes, because the pressure builds up inside and the air want to expand. Letter a)

Hugs!

7 0

3 years ago

What is the weight of an object with a mass of 19 kg?

Natalija [7]

Answer:

Every 2.2 kg is 1 pound. So mulitply 19 * 2.2. It's gonna be equal to 41.8

Explanation:

7 0

2 years ago

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