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Reptile [31]
3 years ago
6

Find the slope of a line through the points (-6, 4) and (3, -4).

Mathematics
1 answer:
stich3 [128]3 years ago
4 0
Do you have a picture would probably make more sense if you added one
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What do I do after I find the implicit differentiation?
Murrr4er [49]

for the implicit integration I got:

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the vertical tangent would at points at which y' goes to infinity.

that happen when the right-hand side has singularities, that is, the denominator is 0:

3y^2-1 =0\\y^2=1/3\\|y|=\sqrt{1/3}\\y=\pm\sqrt{1/3}

so the two points y above have a vertical tangent.


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Debora [2.8K]
I am not 100% positive but from what I remember learning I think the answer you are looking for on the first question is C.
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