Find all solutions in the interval [0, 2π).

1 answer:

4 0

Let tan x = a
7 tan^3 x - 21 tan x = 0 becomes
7a^3 - 21a = 0
7a(a^2 - 3) = 0
a = 0 or a^2 - 3 = 0
a = 0 or a^2 = 3
a = 0 or a = + or - √3

tan x = 0, tan x = √3, tan x = -√3
x = 0, pi, pi/3, 4pi/3, 2pi/3, 5pi/3

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You have 24 months left until you graduate and you plan on buying yourself a new $20,000 car on graduation day. If you invest $3

shusha [124]

Answer: No, the money won't be enough to buy the car

Step-by-step explanation:

you plan on buying yourself a new $20,000 car on graduation day and graduation day is 24 months time. If you invest $300 a month for the next 24 months.

The principal amount, p = 300

He is earning 4% a month, it means that it was compounded once in four months. This also means that it was compounded quarterly. So

n = 4

The rate at which the principal was compounded is 4%. So

r = 4/100 = 0.04

It was compounded for a total of 24 months. This is equivalent to 2 years. So

n = 2

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount that would be compounded at the end of n years.

A = 300(1 + (0.04/4)/4)^4×2

A = 300(1 + 0.01)^8

A = 300(1.01)^8

A = $324.857

The total amount at the end of 24 months is below the cost of the car which is $20000. So he won't have enough money to buy the car

3 0

4 years ago

What is the answer to this word problem??

AveGali [126]

Let’s use m for months
So,
1st service
10m + 20

1. 10 + 20 =30
2. 10x2=20+20=40
3.10x3=30+20=50
4.10x4=40+20=60
5.10x5=50+20=70

2nd service
11m + 15

1. 11+15=26
2. 11x2=22+15=37
3 11x3=33+15=48
4.11x4=44+15=59
5.11x5=55+15=70

So, the 5th month the services cost the same

Hope this helps! ;)

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3 years ago

Boris made $306 for 18 hours of work. At the same rate, how many hours would he have to work to make $119?

Masja [62]

In order to make 119$ he would need to work 7 hours