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MAVERICK [17]
3 years ago
15

Find the area of each figure. Use 3.14 for x.

Mathematics
1 answer:
Serga [27]3 years ago
6 0

8.10/2 + 2.3 = 46 total area is 46

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You have $30 to buy muffins. However, at the shop you can buy 1 muffin for $4. (a) Write an inequality from the above informatio
sattari [20]

Answer:

Let m be the number of muffins.

a) 4m <= 30

b) m <= 7.5, so the maximum number of muffins to buy is 7.

c) $4 × 7 = $28, so $2 will be left over.

8 0
2 years ago
I believe the answer is B can anyone confirm please?
Marizza181 [45]
The answer is D, not B
7 0
4 years ago
Molly is a salaried employee. Her holiday
drek231 [11]

Answer: £3885.71

Step-by-step explanation:

Let x be salary

Holding pay = 17.5% of x = 680.00

X = 680/0.175 = 3885.71

4 0
3 years ago
In what form is the following linear equation written? y-3=2/3(x-1)
lions [1.4K]
First we solve what we can solve.
<span>y</span>-3= 2/3<span>(</span>x-1)
We first multiply
<span>y</span>-3= 2/3 (x) - 2/3
Then we move the -3 and it becomes +3 on the other side
y= 2/3 (x) - 2/3 + 3
And we solve what we can to get our answer.
y= 2/3 (x) + 2 1/3
3 0
3 years ago
Read 2 more answers
Estimate the perimeter of the figure to the nearest whole number.
Paha777 [63]

Answer:

The perimeter (to the nearest integer) is 9.

Step-by-step explanation:

The upper half of this figure is a triangle with height 3 and base 6.  If we divide this vertically we get two congruent triangles of height 3 and base 3.  Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles:  (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.

Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.

The lower half of the figure has the shape of a trapezoid.  Its base is 4.  Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle.  Using the Pythagorean Theorem, we get

(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10.  Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.

Then the perimeter consists of the sum 2√10 + 4 + 6√2.

which, when done on a calculator, comes to 9.48.  We must round this off to the nearest whole number, obtaining the final result 9.

4 0
3 years ago
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