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Ivan
3 years ago
12

A rectangle is shown with length x plus 10 and width 2 x plus 5. The inside of the rectangle is shaded other than an unshaded sq

uare with length x plus 1 and width x plus 1.
Mathematics
2 answers:
evablogger [386]3 years ago
4 0

Answer:

Step-by-step explanation:

I am not sure what your question is asking so I will calculate areas of all three shapes:

Area of the rectange = length * width = (x + 10) * (2x + 5)

= 2x^2 + 25x + 50

Area of the unshaded square within the reactangle

= length * width

= (x + 1) * (x + 1)

= x^2 + 2x + 1

Shaded area inside the rectange

= Area of rectangle - Area of un-shaded square

= (2x^2 + 25x + 50) - (x^2 + 2x + 1)

= x^2 + 23x + 49

klio [65]3 years ago
3 0

Answer:

Step-by-step explanation:

A rectangle is shown with length x plus 10 and width 2 x plus 5.

so the rectangle area = length * width

= (x + 10) * (2x + 5)

an unshaded square with length x plus 1 and width x plus 1

so the unshaded square area = (x + 1) * (x + 1)

the shaded area = rectangle area - square area

= (x + 10) * (2x + 5) - (x + 1) * (x + 1)

= (2x^2 + 20x + 5x + 50) - (x^2 + x + x + 1)

= x^2 + 23x + 49

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Suppose the names of the months of the year are placed in a hat and a name is drawn at random. (a) list the sample space for thi
ollegr [7]

(a)

The sample space is a set whose elements are all the possible outcomes for the experiment. Since we will extract one of the months of the years, the sample space is the set composed by all the 12 months:

\Omega = \{ \text{January},\ \text{February},\ldots,\text{December}\}

(b)

An event is a subset of the sample space. Events are often defined by their properties. In this example, the event E is the subset of the sample space defined as

E = \{ x \in \Omega: x \text{ starts with the letter J}\}

So, we have

E = \{\text{January},\ \text{June},\ \text{July}\}

(c)

If all outcomes have equal probability, then the probability of an event is the ratio bewteen its cardinality, and the cardinality of the whole sample space:

P(E) = \dfrac{n(E)}{n(\Omega)} = \dfrac{3}{12} = \dfrac{1}{4}

In words, since there are three months beginning with J out of 12 months, we have a probability of 3 over 12 to pick a month starting with J, which simplifies to 1 over 4.

3 0
3 years ago
Geometry: fill in the blanks (ASAP!! It’s urgent)
stepladder [879]

5. m∠C = 95°

6. m∠C = 70°

7. The other acute angle in the right triangle = 70°

8. m∠C = 70°

9. m∠C = 60° [equilateral triangle]

10. Measure of the exterior angle at ∠C = 110°

11. m∠B = 70°

12. m∠Z = 70°

<h3>What are Triangles?</h3>

A triangle is a 3-sided polygon with three sides and three angles. The sum of all its interior angles is 180 degrees. Some special triangles are:

  • Isosceles triangle: has 2 equal base angles.
  • Equilateral triangle: has three equal angles, each measuring 60 degrees.
  • Right Triangle: Has one of its angles as 90 degrees, while the other two are acute angles.

5. m∠C = 180 - 50 - 35 [triangle sum theorem]

m∠C = 95°

6. m∠C = 180 - 25 - 85 [triangle sum theorem]

m∠C = 70°

7. The other acute angle in the right triangle = 180 - 90 - 25 [triangle sum theorem]

The other acute angle = 70°

8.  m∠C = 180 - 55 - 55 [isosceles triangle]

m∠C = 70°

9. m∠C = 60° [equilateral triangle]

10. Measure of the exterior angle at ∠C = 50 + 60

Measure of the exterior angle at ∠C = 110°

11. m∠B = 115 - 45

m∠B = 70°

12. m∠Z = 180 - 35 - 75

m∠Z = 70°

Learn more about triangles on:

brainly.com/question/25215131

#SPJ1

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Through: (1,5), perp. to y=-1/10x + 3<br> pls help
Sedbober [7]
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Then you use the formula
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(1,5) with new slope m
5= 10(1)+b
5-10=b
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then make your new equation
y = 10x -5
that's your line that goes through point (1,5) and is perpendicular to the line given
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