A rectangle is shown with length x plus 10 and width 2 x plus 5. The inside of the rectangle is shaded other than an unshaded sq
uare with length x plus 1 and width x plus 1.
2 answers:
Answer:
Step-by-step explanation:
I am not sure what your question is asking so I will calculate areas of all three shapes:
Area of the rectange = length * width = (x + 10) * (2x + 5)
= 2x^2 + 25x + 50
Area of the unshaded square within the reactangle
= length * width
= (x + 1) * (x + 1)
= x^2 + 2x + 1
Shaded area inside the rectange
= Area of rectangle - Area of un-shaded square
= (2x^2 + 25x + 50) - (x^2 + 2x + 1)
= x^2 + 23x + 49
Answer:
Step-by-step explanation:
A rectangle is shown with length x plus 10 and width 2 x plus 5.
so the rectangle area = length * width
= (x + 10) * (2x + 5)
an unshaded square with length x plus 1 and width x plus 1
so the unshaded square area = (x + 1) * (x + 1)
the shaded area = rectangle area - square area
= (x + 10) * (2x + 5) - (x + 1) * (x + 1)
= (2x^2 + 20x + 5x + 50) - (x^2 + x + x + 1)
= x^2 + 23x + 49
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