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Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Solution : Given,
Mass of Cu = 300 g
Molar mass of Cu = 63.546 g/mole
Molar mass of 
= 183.511 g/mole
- First we have to calculate the moles of Cu.
The moles of Cu = 4.7209 moles
From the given chemical formula, we conclude that the each mole of compound contain one mole of Cu.
So, The moles of Cu = Moles of = 4.4209 moles
- Now we have to calculate the mass of .
Mass of = Moles of × Molar mass of = 4.4209 moles × 183.511 g/mole = 866.337 g
Mass of = 866.337 g = 0.8663 Kg (1 Kg = 1000 g)
Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Answer:
One of the errors for low percentage of magnesium could be because not all the magnesium may have reacted.
Explanation:
During the heating process, if the magnesium have not reacted completely, it can lead to low percentage of magnesium in the oxide formed. The product may still look a bit greyish rather than whitish after the heating process.
Height of a mountain is 5348.9 meter.
1 kilometer is equal to 1000 meter.
The meter, symbol m, is the primary unit of period in the international system of gadgets, although its prefixed paperwork also are used relatively regularly.
A meter is a general metric unit identical to about three feet 3 inches. This means that a meter is part of the metric gadget of dimension. Guitars, baseball bats, and backyard sticks are examples of items which might be approximately one meter lengthy. Meters also are used to measure distances in races, inclusive of strolling and swimming.
Meter readings tell power suppliers how a lot gasoline and energy you are the use of. In case you do not give your provider meter readings they may have to guess your usage. You typically turn out to be paying too much or too little while this occurs.
Learn more about meter here:- brainly.com/question/218459
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Answer:
Density is a measure of mass per unit of volume. Density is a measure of mass per volume. The average density of an object equals its total mass divided by its total volume.
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