Answer:
An acid is substance that produces <u>H⁺ </u>ions in solution, which is also written as the hydronium ion <u>H₃O⁺</u>. A base is a substance that produces an ion with the formula <u>OH⁻ </u>and the name <u>hydroxyl</u> ion.
Explanation:
An acid is substance that produces H⁺ ions in solution, which is also written as the hydronium ion H₃O⁺. A base is a substance that produces an ion with the formula OH⁻ and the name hydroxyl ion.
Acid:
An acid is the substance that sour in taste and turns the color of litmus paper from blue to red.
pH of acid is less than seven.
Base:
An acid is the substance that bitter in taste and turns the color of litmus paper from red to blue.
The pH of base is 7-14.
Arrhenius gives the simplest definition of acid and base.
Arrhenius acid:
A substance that increase the concentration of hydronium ion in solution is called acid.
HNO₃ → H⁺ + NO₃⁻
(H₂O)
Arrhenius base:
A substance that increase the concentration of OH⁻ ion in solution is called base.
KOH → K⁺ + OH⁻
The heat of vaporization is when it changes phases from liquid to gas. When it is quite low, it means that it has weak attraction between the liquid particles
53.3% + 6.7% = 60%, 100% - 60% = 40%. 40% of glucose is made of carbon. Since there are only three types of atoms in glucose, and the amount of hydrogen and oxygen is already given, this means that whatever percentage is left (40%) has to be carbon.
Not sure, but I believe it is... Sodium Nitrate?
We have to first write a balanced equation.
so2 + o2 -> so3
this is not balanced though. we have 3 oxygen on right and 4 on left
2so2 + o2 -> 2so3
now it is same on both sides. we have to figure out which is limiting reagent with the given amounts of reagents. we do this by comparing the ratio between them in terms of moles. we see that so2 has a coefficient of 2 and o2 has none which implies 1 and so3 has 2. this means that for every 2 moles of so2 reacting with 1 mole of o2, we get 2 moles of so3.
lets convert the given values to moles. to do this we know that molecular weight is measured in grams per mole. we are given grams and need to cancel out the grams to get moles. so the molecular weight:
so2 =32.1 + 2 * 16 = 64.1 g/mol
o2 = 2 * 16 = 32 g/mol
so3 = 32.1 + 3 * 16 = 80.1 g/mol
now to convert 90 g of 2so2 under ideal conditions.
90g / 64.1g/mol = 1.404 moles
convert this amount of moles of so2 to moles of o2. we have 2 moles of so2 to 1 of o2
1.404moles so2 / 2 moles so2 * 1 mole o2= 0.702 moles o2
so we see under ideal conditions that 90g of so2 would react with .702g of o2. lets see how many we actually have with 100g of o2
100g / 32g/mol =3.16 mol.
so we have a lot more o2 than needed. we are looking for how much is left in grams. we have to figure out how much was used. to do this convert our ideal moles of o2 into grams.
.702 moles o2 * 32g/mol = 22.5g o2
so what we startrd with (100g) minus what we needed (22.5g) is what we have left
100 - 22.5 = 77.5g o2
