Answer:
1.32*10^23 molecules
Explanation:
sucrose formula: C12H22O11
molar mass: 12(12.01)+22(1.01)+11(16.00)=342.34g/mol
75.0 g C12H22O11 * (1 mol C12H22O11)/(342.34g C12H22O11)=0.219 mol C12H22O11
0.219 mol * (6.022*10^23)/mol = 1.32*10^23 molecules (three sig. figures)
Answer:
There is nothing to answer lol
Answer:
rats. that's all i know of Just about everything except the mother hen if they are natural hatch. Even when you incubate them there are threats. The healthy chicks will mob the weak ones, the older chicks (even by a day) will pick on the younger ones. Temperature extremes will threaten them as they need warm, humid conditions with gradual drops in surrounding temps in the brooder box. Early disease is sometimes a problem and all chicks should be started on medicated chick feed for the first few weeks to prevent several digestive diseases. Even the water dispenser can be a threat as newly hatched chicks will immerse themselves in an open water container so care should be taken to supply water in a self feeding covered dish.
Explanation:
The molecular formula of methylpropan-1-ol is C4H10O, so the complete combustion equation is: C4H10O + 6O2 --> 4CO2 + 5H2O. This mean to completely combust 1.0mol of methylpropan-1-ol, 6 mol of O2 is required. Molar mass of O2 is 32 g/mol, so 32g/mol x 6mol = 192 g of O2 is required. At room temperature and pressure, the density of O2 is 1.3315 g/L (this can be obtained by density of gas = P/RT). So the volume of O2 = mass/density = 192g/1.3315(g/L) = 144 L = 144 dm3. The answer is B.
Since transition metals with partially filled d orbitals have color when in solution. Therefore which ever solution has some color will likely contain a transition metal with a partially filled d orbital.
an example of this is solution with Cu²⁺ will have a blue tint to it.
