Ask question

Ask question

All categories

3 years ago

6

Which type of bond results when one or more valence electrons are transferred from one atom to another?

1 answer:

sashaice [31]3 years ago

5 0

Answer:

Electrovalent or ionic bond

Explanation:

For atoms to enter into chemical bonding, they either share, give or receive electrons. When they share electrons, it is a case of covalent bonding. A situation in which they give or take electrons is principally an electrovalent bonding case.

Thus, the type of bond resulting from the transfer of electrons between valence shells of atoms is what we know as electrovalent or ionic bonding. It usually occurs between atoms which have a high value of electronegativity value difference between the atoms such as a case of sodium and chlorine

You might be interested in

Listed below are blood groups of o, a, b, and ab of randomly selected blood donors (based on data from the greater new york bloo

KIM [24]

The answer to this is 22, confirmed by gradpoint

3 0

3 years ago

Read 2 more answers

Calculate the pH of a solution with a [H 3 O + ]=5.6x10 -9 M.

Gre4nikov [31]

Answer:

8.3

Explanation:

pH is the measure of the H+ or H30 (they r the same thing) ions in a solution. it is equal to -log[H+]. [H+]= Molar concentration of H+ ions.

6 0

3 years ago

What has to happen in order for dew to form on grass?

jeka57 [31]

It has to be moist in the grass

4 0

2 years ago

I know this isn't school-related but Is all-purpose flour the same as self-rising flour?

Rainbow [258]

Answer:yes

Explanation:

I am a baker owo

4 0

3 years ago

Read 2 more answers

g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertaint

diamong [38]

Answer:

The value is $L = 0.985 \pm 0.00801 \ g$

Explanation:

From the question we are told that

The molar mass of $CaCO_3$ is $MW = 100.085 \ g/mol$

The total mass is $m_g = 12.3 \ g$

The uncertainty of the total mass is $\Delta g = 0.1$

Generally the molar weight of calcium is $M_c = 40 g/mol$

The percentage of calcium in calcite is mathematically represented as

$C = \frac{40.07}{100.085} * 100$

$C = 40.03 \%$

Generally the mass of each sample is mathematically represented as

$m= \frac{m_g}{5}$

$m= \frac{12.3}{5}$

$m= 2.46 \ g$

Generally mass of calcium present in a single sample is mathematically represented as

$m_c = 2.46 * \frac{40.04}{100}$

$m_c = 0.985 \ g$

The uncertainty of mass of a single sample is mathematically represented as

$k = \frac{\Delta g }{5}$

$k = \frac{0.1 }{5}$

$k = 0.02\ g$

The uncertainty of mass of calcium in a single sample is mathematically represent

$G = \frac{0.02 * 40.04}{ 100}$

$G = 0.00801 \ g$

Generally the average mass of calcium in each sample is

$L = 0.985 \pm 0.00801$

6 0

3 years ago