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Nataly [62]
2 years ago
5

Indicar la cantidad de sustancia en: a) 2.0L de un gas en C.N; b) 22.4 mL de un gas a 755 torr y 26 grados celsius?

Chemistry
1 answer:
nekit [7.7K]2 years ago
8 0

Answer:

El termopar B presenta un mayor grado de dispersión y también es más preciso. ... (c) La estimación para T = 175 ° C es probablemente la más cercana al valor real, porque el ... (cm3). Flujo de masa. Velocidad. (kg / min). Diferencia. Duplicar. (Di). Yo y yo. 2. 1 ... atm de gas. 2. 2. 2 f. 3. 2 f f. 30 14,7 lb 20 pulg. 4 14,7 lb 24 pulg 392 lb 7,00 10 lb pulg.

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To find out how many grams are in 4.65 moles of Al(NO₂)₃
Find out what the molar mass of Al(NO₂)₃ is
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Next, you have to look at the subscripts and figure out which they belong to, in this case:
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N₃ = 42 g/mol N₃
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Finally, add the numbers together, so:
26.98 g/mol Al + 42 g/mol N₃ + 96 g/mol O₆ = 
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Now, you have 4.65 mol Al(NO₂)₃ so
164.98 g/mol Al(NO₂)₃ × 4.65 mol Al(NO₂)₃ =
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