Explanation:
To delineate the the nature of the bonds that would be formed between the two elements, let us first write the electronic configuration of the two species;
Be = 2, 2
F = 2, 7
Beryllium is a metal with two valence electrons whereas fluorine is a halogen with seven valence electrons.
When Be loses two electrons it becomes isoelectronic with He;
Be → Be²⁺ + 2e⁻
Also, when fluorine gains an electron, it becomes isoelectronic with Ne;
F + e⁻ → F⁻
This loss and gain of electrons between the two elements creates an electrostatic attraction them and they enter into an electrovalent bond.
Hence;
Be²⁺ + 2F⁻ → BeF₂
The answer is A because I did this before
The equilibrium constant k is actually the ratio of the
concentration of the products over the concentration of reactants at equilibrium. So if the
concentration of products < concentration of reactants, therefore the
constant k will be small. But if the concentration of products >
concentration of reactants, the constant k will be large. In this case the
value is too small (x10^-19), therefore we can say that the reaction favors the
reactant side:
the equilibrium lies far to the left
The Supreme Court case of Marbury v. Madison
<span>(1803) strengthened the power of the judicial branch by</span> "<span>(4) granting federal courts the power to declare
laws unconstitutional"</span>
