Answer: Thus the new volume of the gas is 530 ml
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of gas = 740 torr
= final pressure of gas = 760 torr
= initial volume of gas = 500 ml
= final volume of gas = ?
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:


Thus the new volume of the gas is 530 ml
Answer:
35.7%
Explanation:
The percent yield is calculated by the formula:
<em>[(actual yield) / (theoretical yield)] * 100</em>
In this case, the actual yield is 0.15 grams, and the theoretical yield is 0.42 grams. So, putting these values into the equation, we have:

Thus, the percent yield of
is 35.7%.
Hope this helps!
Answer:
A solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.
Explanation:
The concentration of a solution in Molarity (M) stands for the number of moles of that substance contained in 1 L of solution.
Molarity = Concentration in mol/L = (Number of moles of solute) ÷ (Volume of solution in L)
Molarity = Concentration in mol/L = 0.105 M = 0.105 mol/L
Number of moles of solute = ?
Volume of solution in L = 1 L
0.105 = Number of moles of solute × 1
Number of moles of solute = 0.105 mole
Hence, a solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.
Hope this Helps!!!
Answer:
<h2>Physical properties: H2SO4 is a colorless or slightly yellow viscous liquid with a pungent odor. It has a density of 1.84 g/mL, boiling point of 337 °C, and melting point of 10 °C. "Concentrated" sulfuric acid is 98% in water, and is the most stable form.</h2>
Hey There!
p-aminophenol (109.13 g/mol) + Ac2O (102.09 g/mol) ---> acetominophen (151.16 g/mol)
next, since you already know your limiting reactant (p-aminophenol), convert it to mols :
0.130 g / (109.13 g/mol) = 0.00119 moles
now that's your theoretical max, since its a 1:1 mol ratio, so multiply by the new molecular weight. :
0.00119 * 151.16 = 0.180 g
Hope that helps!