THe name of this alkane is <span>1-ethyl,3-methylcyclohexane</span>
(4 mol H2O) x (112 kJ / 3 mol H2O) = 149 kJ
<span>(14.5 g HCl) / (36.4611 g HCl/mol) x (112 kJ / 3 mol HCl) = 14.9 kJ </span>
<span>(475 kJ) / (181 kJ / 2 mol HgO) x (216.5894 g HgO/mol) = 1137 g HgO </span>
<span>(179 kJ) / (181 kJ / 1 mol O2) x (31.99886 g O2/mol) = 31.6 g O2 </span>
<span>(145 kJ) / (112 kJ / 3 mol Cl2) x (70.9064 g Cl2/mol) = 275 g Cl2 </span>
<span>(14.5 g S2Cl2) / (135.0360 g S2Cl2/mol) x (112 kJ / 1 mol S2Cl2) = 12.0 kJ </span>
<span>CaCO3 + 2 NH3 → CaCN2 + 3 H2O; ∆H = –90.0 kJ </span>
<span>(798 kJ) / (90.0 kJ / 2 mol HN3) x (17.03056 g NH3/mol) = 302 g NH3 </span>
<span>(19.7 g H2O) / (18.01532 g H2O/mol) x (90.0 kJ / 3 mol H2O) = 32.8 kJ</span>
If the wavelength of the wave is increased to 10 m, the frequency of the wave will be 60 Hz
<h3>Data obtained from the question </h3>
- Wavelength (λ) = 10 m
- Velocity (v) = 600 m/s
<h3>How to determine the frequency of the wave </h3>
The frequency, wavelength and velocity of a wave are related according to the following equation:
Frequency (f) = velocity (v) / wavelength (λ)
f = v / λ
With the above formula, we can obtain the frequency of the wave as follow
f = v / λ
f = 600 / 10
f = 60 Hz
Learn more about wave:
brainly.com/question/2903713
This reaction is known as respiration and in order to understand the stoichometry better, we first write the reaction equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
From the equation, we can see that the molar ratio between glucose and oxygen is 1 : 6. Therefore, we can see that if 6 moles of oxygen are consumed, one mole of glucose will be consumed.
