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3 years ago

15

How can you determine the number of shells in an atom of a certain element, based

1 answer:

netineya [11]3 years ago

5 0

Answer: At some point in your chemistry education, you may have been introduced to the song “The Elements in which Tom Lehrer does a rapid

fire musical rendition of all the elements' names. Like me, you may even have been offered the opportunity to memorize this song for extra credit. If so, it’s possible that you still remember the names of all the elements, which is an impressive feat—not to mention a fun trick to pull out at parties.

Explanation:

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What determines the velocity of an object

maxonik [38]

Answer:

the direction of the object

Explanation:

4 0

3 years ago

Why are intensive properties useful for identifying a substance?

Lesechka [4]

Answer:

d

They do not depend on the amount of substance you have.

3 0

2 years ago

1. Calculate the molar mass of sucrose (C12 H11 O22)?

ohaa [14]

Answer:

=342g

Explanation:

atomic mass of C = 12g

atomic mass of H = 1g

atomic mass of O = 16g

Solution;

C12 H22 O11

= 12 (12) + 22 (1) + 11(16)

= 144+ 22 + 176

= 342g

4 0

2 years ago

A 75 g piece of gold (Au) at 1000 K is dropped into 200 g of H2O at 300K in an insulated container at 1 bar. Calculate the tempe

Deffense [45]

Answer:

The temperature of the system once the equilibrium has been reached = 372.55K

Explanation:

Heat capacity of gold = 129 J/Kg*c.

Heat capacity of water

4,184 J/Kg*c.

Mass of gold = 75g = 0.075Kg

Mass of water = 200g = 0.2Kg

From conservation of energy

m1×C1×(t11 - t2) = m2×C2×(t2- t21)

Substituting we have

0.075 × 129×(1000-t2) = 0.2× 4184×( t2 -300) =solving for t2, we have

933.55×t2 = 347790

or t2 = 372.55K

The temperature of the system once the equilibrium has been reached = 372.55K

6 0

3 years ago

Microwave ovens work by irradiating food with microwaves, which are absorbed by the water molecules in the food and converted to

snow_tiger [21]

Answer:

$7.45\times 10^{26}$ photons are emitted per second in a $1\times 10^3$ Watt microwave oven.

Explanation:

The expression for the power is:-

$Power=\frac{Energy}{Time}$

Also, $E=n\times \frac{h\times c}{\lambda}$

Where,

n = the number of photons

h = Plank's constant having value $6.626\times 10^{-34}\ Js$

c = the speed of light having value $3\times 10^8\ m/s$

$\lambda$ = the wavelength of the light

So,

$Power=\frac{n}{Time}\times \frac{h\times c}{\lambda}$

Thus, the expression for photons per second is:-

$\frac{n}{Time}=\frac{Power\times \lambda}{h\times c}$

Given that:-

Power = 10³ Watt

( 1 cm = 0.01 m)

[/tex]

So,

$Photon/sec=\frac{10^{3}\times 0.148}{6.626\times 10^{-34}\times 3\times 10^8}=7.45\times 10^{26}$

$7.45\times 10^{26}$ photons are emitted per second in a $1\times 10^3$ Watt microwave oven.

7 0

3 years ago