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Phoenix [80]
3 years ago
10

What are the three kind of rocks that are apart of the rock cycle???

Chemistry
2 answers:
Afina-wow [57]3 years ago
8 0
Sedimentary, metamorphic, and igneous

Hope this helps! :)
pav-90 [236]3 years ago
5 0
Why, Hello There! The 3 Kinds of rocks that are apart of the rock cycle is...

1.S<span>edimentary

2.M</span><span>etamorphic

And
</span><span>
 3.Igneous

Hoped i helped!



</span>
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Write the reaction that occurs when propyl methanoate is hydrolyzed in water and in NaOH
Free_Kalibri [48]

An ester , propyl methanoate ( HCOOC₃H₇) when reacts with sodium hydroxide( NaOH) forms sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH).

The reaction is as follows:

HCOOC₃H₇+NaOH ⇒HCOONa + C₃H₇OH

So when propyl methanoate is hydrolyzed in water and in NaOH then sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH) forms

5 0
3 years ago
Ava’s best friend has an indoor cat. Ava notices that she sneezes every time that she visits her friend. Ava suspects that she i
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Answer:

I say for her to test her suspicion by going to see an allergist to diagnose the allergy.

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4 NH3 + 6 NO → 5 N2 + 6 H2O How many moles of NH3 are necessary to produce 0.824 mol N2?
GrogVix [38]
4 mol NH₃ → 5 mol N₂
x mol NH₃ → 0.824 mol N₂

x=0.824*4/5=0.6592 mol
6 0
3 years ago
How many molecules are in 0.500 mole of N2O5?
Oksi-84 [34.3K]

Answer:

3,011.10e23.

Explanation:

3 0
3 years ago
Calculate the energy required to heat of 1.50 kg iron from -7.8 C to 15.0 C . Assume the specific heat capacity of silver under
Leni [432]

Answer : The energy required to heat of 1.50 kg iron is, 1.5\times 10^4J

Explanation :

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat required = ?

m = mass of iron = 1.50 kg  = 1500 g

c = specific heat of iron = 0.450J/g^oC

T_1 = initial temperature  = -7.8^oC

T_2 = final temperature  = 15.0^oC

Now put all the given value in the above formula, we get:

Q=1500g\times 0.450J/g^oC\times (15.0-(-7.8))^oC

Q=15390J=1.5\times 10^4J

Therefore, the energy required to heat of 1.50 kg iron is, 1.5\times 10^4J

6 0
3 years ago
Read 2 more answers
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