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Aleks [24]
4 years ago
5

A 5.0 l sample of gas is cooled from 298 k to 278 k at constant pressure. what is the new volume of the gas?

Chemistry
1 answer:
olga nikolaevna [1]4 years ago
5 0
In order to calculate the final volume of the gas, we may apply Charles Law, which states that for a fixed amount of gas subject to a fixed amount of pressure, the volume and temperature of a gas are directly proportional. This is:
V/T = constant
Using this equation,
5/298 = V/278
V = 4.66 L

The final volume of the gas is 4.66 liters
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n200080 [17]

Answer:

ΔHrxn =  -34,653.33 J /mol

Explanation:

In this question we have to calculate the heat of reaction for

CuSO₄ + 2 KOH ⇒ Cu(OH)₂ + K₂SO₄  

in units of J/mole Cu(OH)₂

Now this heat by the law of conservation of energy is equal to the heat absorbed by the water plus the heat absorbed by the calorimeter. Thus what we need to do first is to calculate those numbers.

Heat absorbed by water

q H₂O = m x c x ΔT

where m is the mass of water mixed, c is the specific heat of water and ΔT is the change in temperature.

Total water volume = 150 mL + 150 mL

m water = 300 mL x 1 g/mL = 300 g

ΔT = T₂ - T₁ = 31.3 ºC - 25.2 º C = 6.1 ºC = 6.1 K

( the change is temperature in K and ºC is the same )

Note that this reaction is exothermic since heat is released which is absorbed by the water and calorimeter because ΔT  is positive.

Now

q H₂O = 300 g x 4.18 J/g·K x 6.1 K = 7649 J

Heat absorbed by the calorimeter

q cal = Ccal x  ΔT = 24.2 J/K x 6.1 K  = 1476 J

Total Heat  = q total = 7649 J + 1476 J = 7797 J

We need to calculate the # moles of Cu(OH)₂ to determine ΔHrxn

M = mol/V ⇒ mol = M x V

mol Cu(OH)₂ = 0.150 L x 1.5 mol/L = 0.225 mol

ΔHrxn = -q total /  mol Cu(OH)₂ = 7797 J / 0.225 mol = -34,653.33 J /mol

Notice ΔHrxn is negative since it is an exothermic reaction.

8 0
4 years ago
For the reactions system 2H2(g) + S2(g) 2H2S(g), a 1.00 liter vessel is found to contain 0.50 moles of H2, 0.020 moles of S2, an
Ne4ueva [31]

Answer:

K = 9.4 *10^5

The reaction favor product formation

Explanation:

Equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium. Also it is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to power equal their stochiometric coefficients.  

so, for the reaction,

  • 2H₂ ₍g₎ + S₂ ₍g₎  → 2H₂S ₍g₎

The equilibrium constant can be expressed as following:

K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}

where  concentration of reactants and products is expressed in molarity Molarity=(no of moles/ Volume L)

So,

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∴ K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=9.4*10^5

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4 0
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