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Burka [1]
3 years ago
6

What is the part of the experiment that is measured? * 2 points control group constant independent variable dependent variable?

Chemistry
1 answer:
Arturiano [62]3 years ago
4 0
The dependent variable is what is being tested. independent is what forces or effects the dependent
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What mass of copper is required to replace silver from 4.00g of silver nitrate dissolved in water?
larisa [96]
The balanced chemical reaction is written as:

<span>Cu +2AgNO3 → Cu(NO3)2 + 2Ag
</span>
We are given the amount of silver nitrate to be used for the reaction. This value will be the starting point of our calculations. It is as follows:

4.00 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Cu / 2 mol AgNO3 ) ( 63.456 g / 1 mol ) = 0.747 g Cu
3 0
3 years ago
A sample of glucose ( C6H12O6 ) of mass 8.44 grams is dissolved in 2.11 kg water. What is the freezing point of this solution? T
taurus [48]

Answer:

<em>- 0.0413°C ≅ - 0.041°C (nearest thousands).</em>

Explanation:

  • Adding solute to water causes the depression of the freezing point.

  • We have the relation:

<em>ΔTf = Kf.m,</em>

Where,

ΔTf is the change in the freezing point.

Kf is the freezing point depression constant (Kf = 1.86 °C/m).

m is the molality of the solution.

<em>Molality is the no. of moles of solute per kg of the solution.</em>

  • <em>no. of moles of solute (glucose) = mass/molar mass</em> = (8.44 g)/(180.156 g/mol) = <em>0.04685 mol.</em>

<em>∴ molality (m) = no. of moles of solute/kg of solvent</em> = (0.04685 mol)/(2.11 kg) = <em>0.0222 m.</em>

∴ ΔTf = Kf.m = (1.86 °C/m)(0.0222 m) = 0.0413°C.

<em>∴ The freezing point of the solution = the freezing point of water - ΔTf </em>= 0.0°C - 0.0413°C = <em>- 0.0413°C ≅ - 0.041°C (nearest thousands).</em>

6 0
3 years ago
what is the ratio of the rate of effusion of helium (atomic mass 4.00 amu) to that of oxygen gas (molecular mass 32.0 amu)?
nignag [31]

Answer:

3 : 1

Explanation:

Let the rate of He be R1

Molar Mass of He (M1) = 4g/mol

Let the rate of O2 be R2

Molar Mass of O2 (M2) = 32g/mol

Recall:

R1/R2 = √(M2/M1)

R1/R2 = √(32/4)

R1/R2 = √8

R1/R2 = 3

The ratio of rate of effusion of Helium to oxygen is 3 : 1

8 0
3 years ago
Identify each of the following household substances as a strong electrolyte, weak electrolyte, or non-electrolyte: salt solution
wolverine [178]

Answer:

Electrolytes are substances that can ionize in water. They could be acids, bases or salts as long as they give ions when they dissolve in water.

Explanation:

  • <em>Strong electrolytes</em> completely ionize when dissolved in water, leaving no neutral molecules. The strong electrolytes here are:<u> salt water</u>, <u>baking soda (NaHCO3) solution.</u>
  • <em>Weak electrolytes</em> do not completely dissociate in solution, and hence have a low ionic yield. Examples of this would be<u> vinegar </u>and <u>bleach </u>(which could be sodium hypochlorite or chlorine, which are weakly dissociated).
  • <em>Non-electrolytes </em>will remain as molecules and are not ionized in water at all. In this case, <u>sugar solution is a non-electrolytes</u>, even though sugar dissolves in water, but it remains as a whole molecule and not ions.

8 0
3 years ago
A gas at 200 K occupies a volume of 350 ml. What temperature is needed to increase the volume
Rudik [331]

Answer: Temperature in constant pressure is 286 K

Explanation: If pressure remains constant, then V/T = constant.

V1 = 350 ml and T1 = 200 K and V2 = 500 ml.  V1/T1 = V2/T2

and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K

5 0
3 years ago
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