Let the first term of the AP be a and the common difference of the AP be d
We know the formula for finding the nth term,
Here,
- an = nth term of the AP
- n = number of terms of AP
By using formula,
- a4 = a + 3d
- a2 = a + d
- a6 = a + 5d
According to given condition,
⇛ a4 = 2a2 - 1
⇛ a + 3d = 2(a + d) - 1
⇛ a + 3d = 2a + 2d - 1
⇛ a - 2a + 3d - 2d = -1
⇛ -a + d = -1
⇛ a - d = 1
Then,
⇛ a = d + 1-----------(1)
It is given that, a6 = 7
⇛ a + 5d = 7
Putting a from eq.(1),
⇛ d + 1 + 5d = 7
⇛ 6d + 1 = 7
⇛ 6d = 6
⇛ d = 6/6 = 1
Putting value of d in eq.(1),
⇛ a = 1 + 1 = 2
⛈ <u>First term of the AP</u><u>(</u><u>a</u><u>)</u><u> = 2</u>
<u>━━━━━━━━━━━━━━━━━━━━</u>
Answer:
BD = 12
Step-by-step explanation:
Answer:
-4
Step-by-step explanation:
-[-12] ÷ [-3] =
= - (4) =
= - 4
Answer:
x = 7 and y = 0
Step-by-step explanation:
We can either solve by substitution method or by elimination method or both method . We will solve by both the elimination and substitution method.
X+y=7 ---------------------------------------------------(1)
-x+y=-7 -------------------------------------------------(2)
Subtract equation (2) from equation(1)
2x = 14
Divide both-side of the equation by 2
2x/2 = 14/2
x = 7
Substitute x = 7 into equation (1)
x+y=7
7 + y = 7
Subtract 7 from both-side of the equation
7-7 + y = 7-7
y = 0
x = 7 and y =0
Answer:
v = 0
Step-by-step explanation:
Solve for v:
7 (5 v + 2) = 3 v + 14
Expand out terms of the left hand side:
35 v + 14 = 3 v + 14
Subtract 3 v from both sides:
(35 v - 3 v) + 14 = (3 v - 3 v) + 14
35 v - 3 v = 32 v:
32 v + 14 = (3 v - 3 v) + 14
3 v - 3 v = 0:
32 v + 14 = 14
Subtract 14 from both sides:
32 v + (14 - 14) = 14 - 14
14 - 14 = 0:
32 v = 14 - 14
14 - 14 = 0:
32 v = 0
Divide both sides of 32 v = 0 by 32:
(32 v)/32 = 0/32
32/32 = 1:
v = 0/32
0/32 = 0:
Answer: v = 0