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4 years ago

When air pressure increases the liquid in a mercury barometer?

Physics

2 answers:

MrMuchimi4 years ago

7 0

It forces the mercury to rise, being pushed up the tube by pressing down on the dish.

I hope I could help :)

maxonik [38]4 years ago

4 0

Answer:

rises

Explanation:

The pressure depends on the height of mercury column raised. It is given by the formula

P = h d g

where, h is the height of mercury, d be the density of mercury and g be the value of acceleration due to gravity.

The density of mercury is constant and the value of acceleration due to gravity is constant, so as the pressure increases the value of height also increases. Thus, the height of liquid in the mercury barometer rises.

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What must the charge (sign and magnitude) of a 1.65 gg particle be for it to remain balanced against gravity when placed in a do

balandron [24]

Answer:

Charge, $q=2.52\times 10^{-5}\ C$ and it is negative.

Explanation:

Given that,

Mass of the charge, $m=1.65\ g=1.65\times 10^{-3}\ kg$

Electric field, E = 640 N/C

To find,

Charge

Solution,

The electric force and the force of gravity are balanced in the electric field. It is given by :

$qE=mg$

$q=\dfrac{mg}{E}$

$q=\dfrac{1.65\times 10^{-3}\times 9.8}{640}$

$q=2.52\times 10^{-5}\ C$

Since, the electric field is in downward direction. The force must be upward direction s that the charge is negative.

5 0

4 years ago

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A typical ten-pound car wheel has a moment of inertia of about 0.35kg⋅m2. The wheel rotates about the axle at a constant angular

QveST [7]

Answer:

The rotational kinetic energy of the rotating wheel is 529.09 J

Explanation:

Given;

moment of inertia I = 0.35kg⋅m²

number of revolutions = 35.0

time of revolution, t = 4.00 s

Angular speed (in revolution per second), ω = 35/4 = 8.75 rev/s

Angular speed (in radian per second), ω = 8.75 rev/s x 2π = 54.985 rad/s

Rotational kinetic energy, K = ¹/₂Iω²

Rotational kinetic energy, K = ¹/₂ x 0.35 x (54.985)²

Rotational kinetic energy, K = 529.09 J

Therefore, the rotational kinetic energy of the rotating wheel is 529.09 J

7 0

3 years ago

I need help with science please, ill give brianlist’s :

Elis [28]

Answer:

true , true, and I'm not sure about the last one!

Explanation:

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3 years ago

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A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0

otez555 [7]

The given question is incomplete. The complete question is as follows.

A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward. Calculate the coefficient of kinetic friction between the box and the floor.

Explanation:

The given data is as follows.

$F_{1}$ = 20 N, $F_{2}$ = 25 N, a = -0.9 $m/s^{2}$