Question

What is the force between two negatively charged objects if q1 = 2.5x10^-6 C, q2 = 4.3x10-6 C and the distance between the charges is 0.04m

Answer 1

The force between the charges is 60.47N

Explanation:

Given:

Charge, q₁ = 2.5 X 10⁻⁶ C

              q₂ = 4.3 X 10⁻⁶ C

Distance, r = 0.04m

Force, F = ?

According to Coulomb's law:

$F = k\frac{q_1q_2}{r^2}$

where,

k = Coulomb's constant

and the value of k is 9 X 10⁹ Nm²/C²

On substituting the value we get:

$F = 9 X 10^9X\frac{2.5 X 10^-^6 X 4.3 X 10^-^6}{(0.04)^2} \\\\F = 60.47N$

Therefore, the force between the charges is 60.47N