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Zarrin [17]
3 years ago
6

C. in the reaction of copper and silver nitrate, a new substance appeared in the test tube. describe the physical appearance of

the substance and identify its chemical formula
Chemistry
1 answer:
forsale [732]3 years ago
6 0
Cu(s) + 2AgNO₃(aq) = Cu(NO₃)₂(aq) + 2Ag(s)

The solution of copper(II) nitrate and metallic silver formed in the reaction. 

Colourless solution becomes blue due to the formation of the copper (II) aquacomplex.

Cu²⁺ + 4H₂O = [Cu(H₂O)₄]²⁺
                            blue

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write down the balanced chemical equation of the reaction that takes place between iron and concentrated sulphuric acid​
pishuonlain [190]

Answer:

2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2

Explanation:

Iron is a metallic element with chemical symbol, Fe while concentrated sulphuric acid is a chemical compound with chemical formula, H2SO4. Both are involved in a chemical reaction as follows:

Fe + H2SO4 → Fe2(SO4)3 + H2

However, this reaction is not balanced as the number of moles of each atom in both the reactants and product side is not equal. To balance the equation, we have to ensure that each number of atom is equal. The balanced equation are as follows:

2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2

5 0
3 years ago
The pressure of a sample of helium in a 200. ml. container is 2.0 atm. If the 5 points
just olya [345]

The pressure of the gas = 40 atm

<h3>Further explanation</h3>

Given

200 ml container

P = 2 atm

final volume = 10 ml

Required

Final pressure

Solution

Boyle's Law  

At a fixed temperature, the gas volume is inversely proportional to the pressure applied  

\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

Input the value :

P₂ = P₁V₁/V₂

P₂ = 2 x 200 / 10

P₂ = 40 atm

3 0
3 years ago
PLeaseee ITS Timedddd + BrainlIESTT
uysha [10]

Answer:

d. 12.3 grams of Al2O3

Explanation:

The balanced chemical equation of this chemical reaction is as follows:

4Al + 3O2 --> 2Al2O3

Based on the balanced equation, 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

First, we need to convert the mass of aluminum to moles using the formula;

mole = mass/molar mass

Molar mass of Al = 27g/mol

mole = 6.50/27

= 0.241mol of Al.

Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.

Convert this mole value to molar mass using mole = mass/molar mass

Molar mass of Al2O3 = 27(2) + 16(3)

= 54 + 48

= 102g/mol

mass = molar mass × mole

mass = 102 × 0.121

mass of Al2O3 = 12.34grams.

5 0
3 years ago
Which profession involves the study and
liq [111]

Answer:

That's easy, science.

Explanation:

5 0
3 years ago
Im hvaing a hard time getting the right answer
Tanya [424]

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

6 0
3 years ago
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