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Vesnalui [34]
3 years ago
14

Name for the compound Ag2S

Chemistry
1 answer:
tankabanditka [31]3 years ago
7 0

The name for the compound Ag2S is Silver sulfide.

<u>Explanation</u>:

  • The name for the compound Ag2S is Silver sulfide. It is the inorganic compound with the formula Ag 2S. A dense black solid, which is used as a photosensitizer in photography.
  • Silver sulfide is insoluble in most solvents but is degraded using robust acids where the bonds have a low ionic of approximately 10%.
  • It has a molar mass of 247.80 g / mol. The look is the grayish-black crystal, odorless, soluble in aqueous HCN, aqueous citric acid with KNO3 and insoluble in acids, alkalies.

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Tara predicts the number of paper clips attracted by the magnet
muminat

The responding variable refers to the variable that changes as the independent variable is being manipulated. In this case, the responding variable is the number of paper clips attracted by the magnet.

An experiment must include a dependent (responding) variable and an independent variable. As the independent variable is manipulated during the experiment, the dependent (responding) variable changes accordingly.

In this case; the independent variable is temperature while the dependent (responding) variable is the number of paper clips attracted by the magnet.

Learn more: brainly.com/question/967776

7 0
3 years ago
I really need help on this question.
natita [175]
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Suggest why it might be difficult and dangerous to test sodium for electrical conductivity?​
lukranit [14]

Answer:

It might cause fire or extreme smoke.

Explanation:

8 0
2 years ago
Solid NaBr is slowly added to a solution that is 0.073 M in Cu+ and 0.073 M in Ag+.Which compound will begin to precipitate firs
saul85 [17]

Answer :

AgBr should precipitate first.

The concentration of Ag^+ when CuBr just begins to precipitate is, 1.34\times 10^{-6}M

Percent of Ag^+ remains is, 0.0018 %

Explanation :

K_{sp} for CuBr is 4.2\times 10^{-8}

K_{sp} for AgBr is 7.7\times 10^{-13}

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.

Now we have to calculate the concentration of bromide ion.

The solubility equilibrium reaction will be:

CuBr\rightleftharpoons Cu^++Br^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Cu^+][Br^-]

4.2\times 10^{-8}=0.073\times [Br^-]

[Br^-]=5.75\times 10^{-7}M

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

AgBr\rightleftharpoons Ag^++Br^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Ag^+][Br^-]

7.7\times 10^{-13}=[Ag^+]\times 5.75\times 10^{-7}M

[Ag^+]=1.34\times 10^{-6}M

Now we have to calculate the percent of Ag^+ remains in solution at this point.

Percent of Ag^+ remains = \frac{1.34\times 10^{-6}}{0.073}\times 100

Percent of Ag^+ remains = 0.0018 %

3 0
3 years ago
What powers explosions and fire
Artyom0805 [142]
Almost always oxidation,
the speed of the reaction is the big difference between fire and explosions
<span>(and slower yet - the "respiration" reactions that keep you alive).</span>
5 0
3 years ago
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