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Alla [95]
3 years ago
13

A student made two solutions – solution A and solution B. Solution A contained 5 g of copper sulfate in 50 cm3 of water. Solutio

n B contains 10 g of copper sulfate in 100 cm3 of water. The student added solution B to solution A. The student concluded that the new solution is more concentrated because it has more copper sulfate dissolved in it Is the student correct? Explain your answer
Chemistry
1 answer:
AlexFokin [52]3 years ago
6 0

Answer:

No. The student is wrong.

Explanation:

Concentration of solution = mole/volume

mole of 5 g of copper = 5/63.546 = 0.0787 mole

Concentration of A = 0.0787/0.05 = 1.57 M

mole of 10 g of copper = 10/63.546 = 0.1574 mole

Concentration of B = 0.1574/0.1 = 1.57 M

The two solution are added together:

Total concentration = total number of mole/total volume

                        = 0.0787 + 0.1574/0.05 + 0.1

                           = 0.2361/0.15

                             = 1.57 M

Hence, the new solution has the same concentration with solution A and solution B.

The student's conclusion was wrong.

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A gas exerts a pressure of 0.62 atm. Convert this to kPa and mmHg. Be sure to show your work.
IRINA_888 [86]

Answer:

The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg

Explanation:

Data

P = 0.62 atm

P = ? kPa

P = ? mmHg

Process

1.- Look for the conversion factor of atm to kPa and mmHg

 1 atm = 101.325 kPa

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2.- Do the conversions

                  1 atm ----------------- 101.325 kPa

                  0.62 atm ------------  x

                   x = (0,62 x 101.325) / 1

                  x = 62.82 kPa

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                   0.62 atm ------------  x

                   x = (0.62 x 760)/1

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Explanation:

This a short problem of solutions:

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