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sukhopar [10]
3 years ago
7

An ionic bond occurs between what particles?

Chemistry
2 answers:
neonofarm [45]3 years ago
7 0

Answer:

This is correct.

atroni [7]3 years ago
4 0

Answer:

A positive and negative ion.

Explanation:

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference.

The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.  Sodium have one valance electron while chlorine have 7 valance electrons. In order to complete the octet chlorine require one electron while sodium need to lose its one electrons. That's why when both atom combine sodium lose its electron and becomes positive ion i.e cation while chlorine accept its electron and becomes negative ion called anion and bond between them is ionic bond.

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Which of the following values best classifies a bond between 2 atoms as<br> being covalent?
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Answer:

C. An electronegativity difference of less than 1.7 between the atoms

Explanation:

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Nitrogen dioxide is one of the many oxides of nitrogen (often collectively called "NOx") that are of interest to atmospheric che
Helga [31]

Answer:

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.

Explanation:

2NO_2(g)\rightleftharpoons N_2O_4(g)

Initially

3.0 atm                 0

At equilibrium

(3.0-2p)                 p

Equilibrium partial pressure of NO_2=2.1atm=3.0-2p

p = 0.45 atm

The value of equilibrium constant wil be given by :

K_p=\frac{p_{N_2O_4}}{(p_{NO_2})^2}=\frac{p}{(3.0-2p)^2}

K_p=\frac{0.45}{(2.1)^2}=0.10

After addition of 1.5 atm of nitrogen dioxide gas equilibrium reestablishes it self :

2NO_2(g)\rightleftharpoons N_2O_4(g)

After adding 1.5 atm of NO_2:

(2.1+1.5) atm                0.45 atm

At second equilibrium:'

(3.6-2P)                     (0.45+P)

The expression of equilibrium can be written as:

K_p=\frac{p'_{N_2O_4}}{(p'_{NO_2})^2}

0.10=\frac{(0.45+P)}{(3.6-2P)^2}

Solving for P:

P = 0.37 atm

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time:

= (0.45+P) atm = (0.45 + 0.37 )atm = 0.82 atm

Partial pressure of dinitrogen tetroxide after equilibrium is reached the second time is 0.82 atm.

5 0
3 years ago
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4 years ago
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