Answer:
6 Cl atoms
Explanation:
In one molecule of ZnCl2, we have 2 atoms of Cl
Therefore, in 3 molecules of ZnCl2, we'll have 3(2) atoms of Cl = 6 atoms of Cl.
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Answer:
28.20 mL of the stock solution.
Explanation:
Data obtained from the question include the following:
Molarity of stock solution (M1) = 12.1 M
Volume of diluted solution (V2) = 350.0 mL
Molarity of diluted solution (M2) = 0.975 M
Volume of stock solution needed (V1) =..?
The volume of stock solution needed can be obtained by using the dilution formula as shown below:
M1V1 = M2V2
12.1 x V1 = 0.975 x 350
Divide both side by 12.1
V1 = (0.975 x 350)/12.1
V1 = 28.20 mL.
Therefore, 28.20 mL of the stock solution will be needed to prepare 350.0 mL of 0.975 M HCl solution.
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Find the Energy of the Photon by Planck's Equation, given:
E (photon energy) =? (in Joule)
h (Planck's constant) = 
f (radiation frequency) =
Therefore, we have:





I Hope this helps, greetings ... DexteR! =)
Answer:
It's compound? It's chemical compound would be represented my letters or numbers