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Tanya [424]
3 years ago
8

When an electron loses electrons it becomes more 1 negative. 2 none of the above. 3 neutral 4 positive.

Chemistry
2 answers:
12345 [234]3 years ago
8 0
The answer would be more positive
olchik [2.2K]3 years ago
8 0
it gonna be more positive
You might be interested in
PLEASE HURRY AND SHOW WORK
IgorC [24]

Answer:

The answer to your question is   P = 1.64 atm

Explanation:

Data

Volume = 2.5 x 10⁷ L

Temperature = 22°C

Pressure = ?

Moles = 1.7 x 10⁶

R = 0.082 atm L/ mol°K

Process

1.- Convert temperature to °K

Temperature = 22 + 273

                      = 295°K

2.- Use the Ideal gas law to solve this problem

                PV = nRT

- Solve for P

                P = nRT / V

- Substitution

                P = (1.7 x 10⁶)(0.082)(295) / 2.5 x 10⁷

- Simplification

                P = 41123000 / 2.5 x 10⁷

- Result

                P = 1.64 atm

3 0
3 years ago
Would the following configuration represent
makvit [3.9K]

Answer:

Excited state

Explanation:

4 0
3 years ago
Which of the following represents the greatest number of atoms?
forsale [732]
The correct option is B. To get the number of atom for each compound, each element in the compound will be counted as an atom. For instance, for Fe[ClO4]2, there are 1 atom of Fe, 2 atoms of Cl, and 8 atoms of O, making a total of 11 atoms [1 + 2 + 8= 11]. The other options have less than 11 atoms. 
7 0
3 years ago
Is heated water more or less dense than the melted snow And rainwater
san4es73 [151]

Answer:

Heated water is more dense than melted snow because water as liquid is denser than ice. Ice floats on water, which means that it has less density than water. Heated water is warmer and more dense than melted ice.

Explanation:

7 0
3 years ago
A 1 mol sample of gas has a temperature of 225K, a volume of 3.3L, and a pressure of 500 torr. What would the temperature be if
serg [7]
<h3>Answer:</h3>

78.75 K

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial pressure, P₁ = 500 torr
  • Initial temperature,T₁ = 225 K
  • Initial volume, V₁ = 3.3 L
  • Final volume, V₂ = 2.75 L
  • Final pressure, P₂ = 210 torr                        

We are required to calculate the new temperature, T₂

  • To find the new temperature, T₂ we are going to use the combined gas law;
  • According to the combined gas law;

P₁V₁/T₁ = P₂V₂/T₂

We can calculate the new temperature, T₂;

Rearranging the formula;

T₂ =(P₂V₂T₁) ÷ (P₁V₁)

  = (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)

  = 78.75 K

Therefore, the new volume of the sample is 78.75 K

5 0
3 years ago
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