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3 years ago

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A detailed explanation, one paragraph of the colligative property being discussed and why that property changes the way that it

does when the amount of solute is increased.
A detailed description, at least one paragraph, of a real-world application of the colligative property, including an explanation of how this application of the colligative property is important or useful to those affected. The real-world example must be one that was not mentioned in the lesson.

1 answer:

levacccp [35]3 years ago

6 0

<span>
You can do it on the icing of roads, reverse osmosis for desalination of water, dissolved CO2 in soda cans, osmotic pressure involving blood vessels and IV solutions, etc.</span>

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Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r

denis23 [38]

Answer :

(1) The frequency of photon is, $3\times 10^{10}Hz$

(2) The energy of a single photon of this radiation is $1.988\times 10^{-23}J/photon$

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = $1.0cm=0.01m$ (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of photon

$\lambda$ = wavelength of photon

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$\nu=\frac{3\times 10^8m/s}{0.01m}$

$\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz$ $(1Hz=1s^{-1})$

The frequency of photon is, $3\times 10^{10}Hz$

(2) Now we have to calculate the energy of photon.

Formula used :

$E=h\times \nu$

where,

$\nu$ = frequency of photon

h = Planck's constant = $6.626\times 10^{-34}Js$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})$

$E=1.988\times 10^{-23}J/photon$

The energy of a single photon of this radiation is $1.988\times 10^{-23}J/photon$

(3) Now we have to calculate the energy in J/mol.

$E=1.988\times 10^{-23}J/photon$

$E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)$

$E=11.97J/mol$

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0

3 years ago

Read 2 more answers

Which of the following is/are true regarding initial and maximal velocity of enzyme-mediated reactions?

kenny6666 [7]

Answer:

a. True

b. True

c. False

d. True

Explanation:

a). A a very low substrate concentration , $$S$ . Thus according to the Machaelis-Menten equation becomes

$V_0 = \frac{V_{max} \times [S]}{Km}$

Here since the $V_0$ varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option (a) is true.

b). The Michaelis -Menten kinetics equation states that :

$V_0 = \frac{V_{max} \times [S]}{Km+[S]}$

Here the initial velocity changes directly with the substrate concentration as $V_0$ is directly proportional to [S]. But $V_{max}$ is same for any particular concentration of the enzymes. Thus, option (b) is true.

c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.

d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.

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2 years ago

Please help ————//-//

grandymaker [24]

Probably b because soil can’t be the exact same and so that cancels out a and d

6 0

2 years ago

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Which of the following has no electrons? Use a periodic table. Question 1 options: H He H– He 2+ Save

Elodia [21]

An electron is a negatively charged subatomic particle present in the space outside the nucleus of an atom. The loss of electron from an atom results in the formation of cation whereas gaining of electron by an atom results in the formation of anion. The cation possesses positive charge due to loss of electron and anion possesses negative charge due to gain of electron.

The neutral atom has no charge on it.

For given atomic symbols:

$H$

The atomic number of hydrogen is 1 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in $H$ is 1.

$He$

The atomic number of helium is 2 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in $He$ is 2.

$H^{-}$

The atomic number of hydrogen is 1 and the given symbol has a negative charge that represents a gain of electron. So, the number of electrons in $H^{-}$ is 2.

$He^{2+}$

The atomic number of helium is 2 and the given symbol has two positive charge that represents loss of two electrons. So, the number of electrons in $He^{2+}$ is 0.

Hence, $He^{2+}$ has no electrons.

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3 years ago

Which of the following is the correctly balanced chemical equation for the reaction of Ca(OH)2 and HNO3?

sattari [20]

Explanation:

The reaction between calcium hydroxide and nitric acid is as follows.

$Ca(OH)_{2} + HNO_{3} \rightarrow Ca(NO_{3})_{2} + H_{2}O$

Number of reactant atoms are as follows.

Ca = 1
O = 4
H = 3
N = 1

Number of product atoms are as follows.

Ca = 1
O = 4
H = 2
N = 3

To balance the given chemical equation, multiply $HNO_{3}$ by 2 on reactant side and multiply $H_{2}O$ by 2 on the product side.

Therefore, the balanced chemical equation will be as follows.

$Ca(OH)_{2} + 2HNO_{3} \rightarrow Ca(NO_{3})_{2} + 2H_{2}O$

4 0

3 years ago