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Paul [167]
3 years ago
8

A detailed explanation, one paragraph of the colligative property being discussed and why that property changes the way that it

does when the amount of solute is increased.
A detailed description, at least one paragraph, of a real-world application of the colligative property, including an explanation of how this application of the colligative property is important or useful to those affected. The real-world example must be one that was not mentioned in the lesson.
Chemistry
1 answer:
levacccp [35]3 years ago
6 0
<span>
You can do it on the icing of roads, reverse osmosis for desalination of water, dissolved CO2 in soda cans, osmotic pressure involving blood vessels and IV solutions, etc.</span>
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2. What does the text list and describe?
Mariana [72]

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C. ways radiation is transferred into and through Earth's atmosphere

Explanation:

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What advantage does having ultraviolet vision give bees?
nikdorinn [45]
Ultraviolet helps bee's see depth and they can see 3 dimensional, they can also see long distance. Bee's have have single lenses that helps the bee maintain stability and navigate. 

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- Hope this helps!

3 0
3 years ago
Many oxidation-reduction reactions can be balanced by inspection. Try to balance the following reactions by inspection. In each
Phoenix [80]

Answer:

Balanced reaction: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

Reduced: O₂

Oxidized : C₃H₈

Explanation:

For the given reaction:

C₃H₈(g) + O₂(g) → CO₂(g) + H₂O(l)

In the reactants, there are 3 C, and in the products only one, so we multiply CO₂ by 3:

C₃H₈(g) + O₂(g) → 3CO₂(g) + H₂O(l)

In the reactants, there are 8 H, and in the products, there are 2 H, so we multiply H₂O by 4:

C₃H₈(g) + O₂(g) → 3CO₂(g) + 4H₂O(l)

In the reactants are 2 O, and in the products 10 O, so we multiply O₂ by 5:

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

The reaction is balanced.

Let's identify the oxidation number (Nox) of the elements in each compound.

C₃H₈:

H has fix Nox equal to +1, and the molecule is neutral, so, calling x the Nox of C:

3x + 8 = 0

3x = -8

x = -8/3

O₂:

Because is a pure compound, the Nox of O is 0.

CO₂:

The Nox of O is fix equal to -2, and the molecule is neutral, so, calling x the Nox of C:

2x -4 = 0

2x = 4

x = +2

H₂O:

The Nox of H and O are fixed, respectively, +1 and -2.

So, the carbon in C₃H₈ is oxidized because its Nox is increasing, and oxygen in O₂ is reduced because its Nox is decreasing.

6 0
3 years ago
A bar of copper has a mass of 216g and a volume of 24cm^3. What is the density of copper?
7nadin3 [17]

Answer:

<h2>The answer is 9 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 216 g

volume = 24 cm³

The density is

density  =  \frac{216}{24}   \\

We have the final answer as

<h3>9 g/cm³</h3>

Hope this helps you

3 0
3 years ago
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