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3 years ago

15

A pipe originally has a radius of 1.25m. It narrows down to a radius of 0.55m. If the original force in the big pipe is 72N, wha

t is the force in the narrow part of the pipe?

1 answer:

Gemiola [76]3 years ago

5 0

Use direct proportionality: If 1.25 m = 72 N, then 0.55 m = y

0.55 m × 72 = 39.6.

39.6÷1,25 gives you your answer which is 31.68 N.

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