Answer:
210 m
Explanation:
Given:
a = -6.8 m/s²
v₀ = 54 m/s
v = 0 m/s
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (54 m/s)² + 2 (-6.8 m/s²) Δx
Δx ≈ 210 m
Using the mirror formula.
1/v + 1/u = 1/f
1/9.5 + 1/3.2 = 1/f
1/f = 3.2 + 9.5 / 9.5 * 3.2
1/f = 4.82 cm
Radius = 2f
Radius = 2 x 4.82
Radius = 9.64 cm
Answer:
500 Ns
Explanation:
According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on it. Mathematically:
where
is the change in momentum of the object
I is the impulse exerted, which is the product of
F, the net force exerted
, the time interval during which the force is applied
In this problem,
F = 100 N is the force applied on the wagon
is the time interval
Substituting, we find the change in momentum of the wagon:
Answer:
a) F = 62.2 N
, b) W = 973.2 J
, c) W = -943.3 J and d) W = 0 J
Explanation:
Work is a scalar that is obtained from the scalar product of two vectors, force and displacement. the bold are vectors
W = F.d = F d cos θ
a) As the car travels at constant speed the acceleration is zero
Fx -fr = 0
Fx = fr
Cos θ = Fx / F
F cos θ = fr
F = fr / cos θ
F = 52.7 / cos 32.1
F = 62.2 N
Is the force exerted by the person
b) Let's calculate the thrust force jobs
W = 62.2 17.9 cos 32.1
W = 973.2 J
c) The force of friction that opposes the movement and is on the x-axis
W = fr d cos 180
W = 52.7 17.9 cos 180
W = -943.3 J
d) The force of gravity that is vertical and has an angle of 90º with respect to the displacement
W = mg d cos 90
W = 0 J
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