Answer:
The current in the circuit decrease slowly .
Explanation:
Given as :
For the electrical circuit
The voltage V in the circuit is slowly decreasing
The resistance R of the resistor slowly increasing after heating
Now, From Ohm's Law
Voltage is directly proportional to the flow of current through circuit
I.e V ∝ I
Or. V = R × I
where R is the proportionate constant and this is the resistance of the resistor
whose property is to opposes the flow of current in the circuit
So, If R value more then current I reduces in the circuit
∵ Here in the circuit , The resistance is slowly increasing, so, current I is slowly decreasing .
Hence The current in the circuit decrease slowly . answer
Answer: 1.04N
Explanation:
Given
q1 = 2*10^-6C
q2 = 3.6*10^-6C
r = 0.25m
k = 9*10^9
Magnitude of electrostatic force can be calculated by using coulomb's law. Coulomb's law states that, "the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them."
F =(kq1q2) / r²
F = (9*10^9 * 2*10^-6 * 3.6*10^-6) / 0.25²
F = 0.0648/0.0625
F = 1.04N
The type of electrostatic force between the charges is the repulsive force
When the temperature lowers the plants can freeze and die. One way to prevent that is to cover the plants so they dont freeze
Answer:
there are 25 kg objective travelling at 2m/s to the right.
Answer:
Q = 1057.5 [cal]
Explanation:
In order to solve this problem, we must use the following equation of thermal energy.
where:
Q = heat energy [cal]
Cp = specific heat = 0.47 [cal/g*°C]
T_final = final temperature = 32 [°C]
T_initial = initial temperature = 27 [°C]
m = mass of the substance = 450 [g]
Now replacing:
![Q=450*0.47*(32-27)\\Q=1057.5[cal]](https://tex.z-dn.net/?f=Q%3D450%2A0.47%2A%2832-27%29%5C%5CQ%3D1057.5%5Bcal%5D)
