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WITCHER [35]
2 years ago
12

(100 answers for this and i reward everyone with a Shoutout on Youtube)

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
6 0
128590 people at the zoo
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What is the leading coefficient in 1-2x+5x^4 when in standard form
Vera_Pavlovna [14]
That's a lot of points for this question. You don't have to offer that much. 

Leading Coefficient: When written in standard form (starting with the variable with the highest power, going to the variable with the next highest power ... all the way down to a number with no variable), the leading coefficient is the number in front of the variable with the highest power. 

Let me put this less technically. Find the variable with the highest power. The number in front of that variable is the leading coefficient.

Write this in standard form. 5x^4 -2x + 1
The number in front of the x^4 is the answer.
5 <<<<< answer 
4 0
2 years ago
When you flip 1/6 it is?
prohojiy [21]
Reciprocal
1/6 turns into 6/1 which is 6
5 0
3 years ago
Read 2 more answers
Uzanne can work 10 math problems in 15 minutes. How many can she work in an hour and a half?
jeyben [28]
1 and half hour
= 60 minutes+ 30 minutes
= 90 minutes

Now,

Uzanne need 15 minutes to do 10 problems
Uzanne need 1 minute to complete 10/15 problems

Uzanne need 90 minutes to do
= (10/15)*90
=(2/3)*90
=2*30
=60 problems
4 0
3 years ago
I need help on 26, 27, 28, and 29
gogolik [260]

Answer:

29- x=59

Step-by-step explanation:

4 0
2 years ago
Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2
kondaur [170]

<u>Answer: </u>

The solution of \bold{\frac{M^{2}}{P^{2}}} for M = 10, N = -5P and P = -2  is 25

<u>Solution: </u>

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of \frac{M^{2}}{P^{2}},  

By substituting the values of M and N, we get

\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}

Expanding \bold{10^{2}}:

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

10^{2} = 10 \times 10 = 100

Similarly expanding \bold{(-2)^{2}}:

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.  

(-2)^{2} = -2 \times -2 = 4

So the equation \frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}} becomes,

\frac{M^{2}}{P^{2}} = \frac{100}{4}

By dividing 100 by 4 , we get the result as 25

Hence the solution of \bold{\frac{M^{2}}{P^{2}}} when M = 10 and P = -2 is 25

6 0
3 years ago
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