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Rainbow [258]
3 years ago
13

A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source

of the electric field, what is the electric potential energy of the charge?
Physics
2 answers:
Nana76 [90]3 years ago
5 0
The formula for electric potential energy is given by:

U_e=k \frac{q_1 q_2}{r}

where:
U_e is the electric potential energy in Joules
k is the Coulomb's constant 9×10⁹ 
q_1 and q_2 are the amoun of charge
r is the distance between the charges

we have:
q_1 = 4.5 × 10⁻⁵
q_2 = 2.0 × 10⁴
r = 0.030

Substitute these values into the formula, we have:

U_e=(9*10^9) \frac{(4.5*10^{-5})(2*10^4)}{0.030}
U_e=2.7*10^{11} Joules
Katen [24]3 years ago
4 0
Can confirm that .027 is the correct answer!
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