Answer:
The period of that same pendulum on the moon is 12.0 seconds.
Explanation:
To determine the period of that same pendulum on the moon,
First, we will determine the value of g (which is a measure of the strength of Earth's gravity) on the Moon. Let the value of g on the Moon be
.
From the question, the strength of earth’s gravity is only 1/6th of the normal value. The normal value of g is 9.8 m/s²
∴
= ![\frac{1}{6} \times 9.8 m/s^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%20%5Ctimes%209.8%20m%2Fs%5E%7B2%7D)
= 1.63 m/s²
From the question, T=2π√L/g
![T = 2\pi \sqrt{\frac{L}{g} }](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7BL%7D%7Bg%7D%20%7D)
We can write that,
.......... (1)
Where
is the period of the pendulum on Earth and
is the measure of the strength of Earth's gravity
and
.......... (2)
Where
is the period of the pendulum on Moon and
is the measure of the strength of Earth's gravity on the Moon.
Since we are to determine the period of the same pendulum on the moon, then,
and
are constants.
Dividing equation (1) by (2), we get
![\frac{T_{E} }{T_{M} } = \sqrt{\frac{g_{M} }{g_{E} } }](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7BE%7D%20%7D%7BT_%7BM%7D%20%7D%20%3D%20%5Csqrt%7B%5Cfrac%7Bg_%7BM%7D%20%7D%7Bg_%7BE%7D%20%7D%20%7D)
From the question,
![T_{E} = 4.9secs](https://tex.z-dn.net/?f=T_%7BE%7D%20%3D%204.9secs)
= 9.8 m/s²
= 1.63 m/s²
= ??
From,
![\frac{T_{E} }{T_{M} } = \sqrt{\frac{g_{M} }{g_{E} } }](https://tex.z-dn.net/?f=%5Cfrac%7BT_%7BE%7D%20%7D%7BT_%7BM%7D%20%7D%20%3D%20%5Csqrt%7B%5Cfrac%7Bg_%7BM%7D%20%7D%7Bg_%7BE%7D%20%7D%20%7D)
![\frac{4.9}{T_{M} } = \sqrt{\frac{1.63}{9.8} }](https://tex.z-dn.net/?f=%5Cfrac%7B4.9%7D%7BT_%7BM%7D%20%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B1.63%7D%7B9.8%7D%20%7D)
![\frac{4.9}{T_{M} } = 0.40783](https://tex.z-dn.net/?f=%5Cfrac%7B4.9%7D%7BT_%7BM%7D%20%7D%20%3D%200.40783)
![T_{M} =\frac{4.9}{0.40783 }](https://tex.z-dn.net/?f=T_%7BM%7D%20%3D%5Cfrac%7B4.9%7D%7B0.40783%20%7D)
![T_{M} = 12.01 secs](https://tex.z-dn.net/?f=T_%7BM%7D%20%3D%2012.01%20secs)
∴ ![T_{M} = 12.0secs](https://tex.z-dn.net/?f=T_%7BM%7D%20%3D%2012.0secs)
Hence, the period of that same pendulum on the moon is 12.0 seconds.
Answer: The pattern of the battery is wrong, the bulb is broken , the wires of the circuit is broken , the switch is not closed .
In my opinion i think it is water
Wave speed is 8 m/s
Explanation:
- Wave speed or speed of the wave is given by the formula
v = distance traveled by the wave/time
- Here, distance traveled = 16 m and time = 2 s
⇒ Wave speed = 16/2 = 8 m/s