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maria [59]
3 years ago
14

Riding his bike, dewayne can start from rest and get going at 12m/s in 4 seconds. Beth can get going 16m/s in 5 seconds. Who has

a greater acceleration? How do you know?
Physics
2 answers:
Angelina_Jolie [31]3 years ago
8 0

<u>Answer:</u> The acceleration of Beth is more than the acceleration of Dewayne.

<u>Explanation:</u>

Acceleration is defined as the rate of change of velocity with respect to time.

Mathematically,

a=\frac{v-u}{t}

where,

v = final velocity

u = initial velocity

t = time taken

  • <u>For Dewayne:</u>

We are given:

v=12m/s\\u=0m/s\\t=4sec

Putting values in above equation, we get:

a=\frac{12-0}{4}=3m/s^2

Acceleration of Dewayne = 3m/s^2

  • <u>For Beth:</u>

We are given:

v=16m/s\\u=0m/s\\t=5sec

Putting values in above equation, we get:

a=\frac{16-0}{5}=3.2m/s^2

Acceleration of Beth = 3.2m/s^2

Hence, the acceleration of Beth is more than the acceleration of Dewayne.

sweet [91]3 years ago
5 0

Answer: Beth

Explanation: Dewayne (a) = 12/4 = 3m/s^2.

Beth (a) = 16/5 = 3.2 m/s^2.

So, Beth is the answer.

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A coil is wrapped with 300 turns of wire on the perimeter of a circular frame (radius = 8.0 cm). Each turn has the same area, eq
MAVERICK [17]

Answer:

Approximately 18 volts when the magnetic field strength increases from \rm 20\; mT to \rm 80\;mT at a constant rate.

Explanation:

By the Faraday's Law of Induction, the EMF \epsilon that a changing magnetic flux induces in a coil is:

\displaystyle \epsilon = N \cdot \frac{d\phi}{dt},

where

  • N is the number of turns in the coil, and
  • \displaystyle \frac{d\phi}{dt} is the rate of change in magnetic flux through this coil.

However, for a coil the magnetic flux \phi is equal to

\phi = B \cdot A\cdot \cos{\theta},

where

  • B is the magnetic field strength at the coil, and
  • A\cdot \cos{\theta} is the area of the coil perpendicular to the magnetic field.

For this coil, the magnetic field is perpendicular to coil, so \theta = 0 and A\cdot \cos{\theta} = A. The area of this circular coil is equal to \pi\cdot r^{2} = \pi\times 8.0\times 10^{-2}\approx \rm 0.0201062\; m^{2}.

A\cdot \cos{\theta} = A doesn't change, so the rate of change in the magnetic flux \phi through the coil depends only on the rate of change in the magnetic field strength B. The size of the magnetic field at the instant that B = \rm 50\; mT will not matter as long as the rate of change in B is constant.

\displaystyle \begin{aligned} \frac{d\phi}{dt} &= \frac{\Delta B}{\Delta t}\times A \\&= \rm \frac{80\times 10^{-3}\; T- 20\times 10^{-3}\; T}{20\times 10^{-3}\; s}\times 0.0201062\;m^{2}\\&= \rm 0.0603186\; T\cdot m^{2}\cdot s^{-1}\end{aligned}.

As a result,

\displaystyle \epsilon = N \cdot \frac{d\phi}{dt} = \rm 300 \times 0.0603186\; T\cdot m^{2}\cdot s^{-1} \approx 18\; V.

9 0
4 years ago
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gogolik [260]

Answer

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Some parts of the earth are prompt to earthquakes, volcanic eruptions landslides and magma movements etc. All this may cause energy movements through the earth inform of a wave. These type of waves are called seismic waves.



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jonny [76]

The answer would be false

3 0
4 years ago
What does a machine change to make work easier? Check all that apply. the amount of work done the amount of force applied the ti
raketka [301]

The correct options are:

2.) the amount of force applied

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A child attempts to roll a ball up a long ramp and it slows as it goes up. If it is released at 2.5 m/s upward and accelerates d
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Answer:

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v=2.5+-0.8*4

v=2.5-3.2

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