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IgorC [24]
4 years ago
6

Heterotrophs convert solar energy into chemical energy. a. True b. False

Physics
1 answer:
jonny [76]4 years ago
3 0

The answer would be false

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3 years ago
Ann walks 80 meters on a straight line 33degrees north of east starting at point 1. Draw Ann's path. Represent Ann's walk with a
zubka84 [21]
The x-component of Anne's path:
80 x cos(33)
= 67.1 meters
y-component of Anne's path:
80 x sin(33)
= 43.6 meters
To draw he diagram, you draw a horizontal line starting at point 1 to the right representing 67.1 meters. At the end of this line, draw a vertical line upwards representing 43.6 meters.
Connect the start of the horizontal line at point 1 to the end of the vertical line with an angle of 33° between them.
7 0
3 years ago
If u add 1.362 and 25.2 what is the correct answer?
krek1111 [17]

Answer:

26.562

Explanation:

1+25= 26

0.362+0.2= 0.562

26+0.562= 26.562

or just use a calculator

6 0
2 years ago
I need help!!!!!!!!! Somebody please help me!!!!!!!!!!!!!
konstantin123 [22]
Voltage, measured in volts (V), is a measure of how much energy is given to the moving electrons in a circuit. Another way of thinking of voltage is by analogy with the pressure that pushes water through the pipes in a house.
8 0
3 years ago
The air within a piston equipped with a cylinder absorbs 565 J of heat and expands from an initial volume of 0.12 L to a final v
Alenkinab [10]

Answer:

The change in internal energy of the air within the piston is 490 J.

Explanation:

In thermodynamics the internal energy (ΔU) of a system is the total energy contained in the system and can be considered as the sum of the energy in the form of heat (q, given to or released by the system) and in the form of work (w, make by the system to the environment or from the environment to the system). When the system absorbs heat from the enviroment this value is positive, while when the system realeased heat to the enviroment, the value is negative. In the case of work, when the enviroment make work on the system, the value is positive and, on the contrary, when the system makes work against the environment the value is negative.

                                           ΔU = q + w

w is defined as the negative product between the external pressure (P) and the change in volume (ΔV). [w = - P·ΔV]

                                       ⇒ ΔU = q - P·ΔV

In this problem, the system is composed by the cylinder + piston + contained air (Attached)

1) q= 565 J (a positive value because the enviroment delivered heat to the cylinder)

2) P = 1 atm.

3) ΔV = 0.86 atm.L - 0.12 atm.L = 0.74 atm.L.

⇒ ΔU = q + w ⇒ ΔU = 565 J - (1 atm)·(0.74 L) ⇒ ΔU = 565 J - 0.74 atm.L

We have to express the work value in the same units of heat, it means Joules. As one joule is equal to 0.00987 atm.L

⇒ (0.74 atm.L) x ( 1 J/0.00987 atm.L) = 74.97 J.

⇒ ΔU = q + w ⇒ ΔU = 565 J - 74.97 J ⇒ ΔU = 490 J.

Summarizing, the change in internal energy of the air within the piston is 490 J.

3 0
3 years ago
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