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nasty-shy [4]
3 years ago
8

The election of 2008 had a record-breaking number of voters. It had the highest percentage of eligible voters voting in more tha

n
a decade. What is one thing that could have cause the 2008 election to have a higher turnout than 2000, 2004, and 2012?

People felt the need to vote out the incumbent.

People wanted to vote in a presidential election.

People wanted to keep the same political party in power.

People were particularly motivated by one of the candidates.

Physics
1 answer:
babunello [35]3 years ago
4 0

Answer:

People were particularly motivated by one of the candidates

Explanation:

The voter turnout in 2008 spiked because people were particularly motivated by Barrack Obama. His running for presidential position represented a <em>"generational change."</em> So, this means that many of the voters, especially the African-Americans ages 18 to 25 years old became interested in registering in order to vote.

Such kind of voter turnout spike is said to have also occurred during the candidacy of John F. Kennedy, where the voter turnout was<em> 62.8 percent.</em> This was because Kennedy was a <em>charismatic leader</em> who also represented a <u>generational change</u>.

So, this explains the answer.

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Calculate the induced electric field (in V/m) in a 40-turn coil with a diameter of 11 cm that is placed in a spatially uniform m
Naddik [55]

Answer:

Explanation:

Given that,

Number of turn N = 40

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r = 0.055m

Then, the area is given as

A =πr²

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so we want to find induce electric field. To find the electric field,(E) we need to find the electric potential (V).

E.M.F is given as

ε = —N • dΦ/dt

Where magnetic flux is given as

Φ = BA

Then, ε = —N • dΦ/dt

ε = —N • dBA/dt

ε = —NBA/t

Then, its magnitude is

ε = NBA/t

Inserting the values of N, B, A and t

ε = 40×0.35×9.503×10^-3/0.1

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