Answer:
the electric field is 42.8×10^6 N/C
Explanation:
let k be the coulomb constant, Q be the charge distribution , R be the radius of the disk and x be the distance from the center.
k = 8.98755×10^9 N×m^2/c^2
Q = 6.1×10^-6 C
R = 4.9×10^-2 m
x = 3.1×10^-3 m
The point midway between the two charges is located 15.0 cm from one charge and 15.0 from the other charge. The electric field generated by each of the charges is
where
ke is the Coulomb's constant
Q is the value of the charge
r is the distance of the point at which we calculate the field from the charge (so, in this problem, r=15.0 cm=0.15 m).
Let's calculate the electric field generated by the first charge:
While the electric field generated by the second charge is
Both charges are positive, this means that both electric fields are directed toward the charge. Therefore, at the point midway between the two charges the two electric fields have opposite direction, so the total electric field at that point is given by the difference between the two fields:
Answer:
D. 2.5 m
Explanation:
1.5 m up to the beam + 0.5 m up + 0.5 m down = 2.5 m total
Answer:
Vx = 35.31 [km/h]
Vy = 18.77 [km/h]
Explanation:
In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.
In order to find the vertical component, we must use the sine function of the angle.