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musickatia [10]
3 years ago
14

Erica (38 kg ) and danny (43 kg ) are bouncing on a trampoline. just as erica reaches the high point of her bounce, danny is mov

ing upward past her at 4.7 m/s . at that instant he grabs hold of her.part awhat is their speed just after he grabs her?
Physics
1 answer:
AfilCa [17]3 years ago
4 0
<span>2.5 m/s going upward.
   In the situation described, Erica and Danny undergo a non-elastic collision which will conserve their combined momentum. Since Erica is stationary, her momentum is 0. And since Danny is moving upward at 4.7 m/s his momentum is 43 kg * 4.7 m/s = 202.1 kg*m/s. Assuming that both Erica and Danny will be moving as a joined system, their combined mass is 38 kg + 43 kg = 81 kg. Since the momentum will be the same, their velocity will be 202.1 kg*m/s / 81 kg = 2.495061728 m/s. Since we only have 2 significant figures in the provided data, rounding the result to 2 significant figures gives a velocity of 2.5 m/s going upward.</span>
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Answer:

a) The final velocity is 20 m/s when the large-mass object is the one moving initially.

b) The final velocity is 9.0 m/s when the small-mass object is the one moving initially.

Explanation:

The momentum of the system is calculated as the sum of the momenta of each object. Each momentum is calculated as follows:

p = m · v

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p =  momentum.

m =  mass.

v = velocity.

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v1 = velocity of the bigger object.

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Solving the equation for the final velocity:

(m1 · v1 + m2 · v2)/ (m1 + m2) = v

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b) When the smaller object is moving:

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<u>v = 9.0 m/s</u>

7 0
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