Answer:
Explanation:
position
y(t) = 2.80t + 0.61t³
velocity is the derivative of position
v(t) = 2.80 + 1.83t²
acceleration is the derivative of velocity
a(t) = 3.66t
F = ma = 5.50(3.66(4.10)) = 82.533 N
which should be rounded to no more than three significant digits and arguably only two due to the 0.61 factor.
F = 82.5 N or 83 N
Yes the units are Newtons, cannot tell what your system will accept. May not want the units at all.
Answer:
the answer would be 2
Explanation:
it would be 2 because if u look at the diagram the darkest arrow is pointsin towards earth and the moon and when the moon is infront of the sun it cause's an eclispe
Answer:
Essentially all of it
Explanation:
The potential energy was
PE = mgh = 6.36(9.81)(2.05) = 127.90278 = 128 J
ignoring air resistance, this PE converts to KE
With no rebound final velocity is zero, so Kinetic energy lost = 128 J
Answer:
Torque = 99.48 N-m²
Explanation:
It is given that,
Radius of the flywheel, r = 1.93 m
Mass of the disk, m = 92.1 kg
Initial angular velocity, 
Final angular speed, 
We need to find the constant torque required to stop it in 1.25 min, t = 1.25 minutes = 75 seconds
Torque is given by :
...........(1)
I is moment of inertia, for a solid disk, 
is angular acceleration
..............(2)
Now finding the value of angular acceleration as :
..........(3)
Using equation (2) and (3), solve equation (1) as :
So, the torque require to stop the flywheel is 99.48 N-m². Hence, this is the required solution.
Answer:
first is regular reflection and 2nd is irregular
