Question number 30 please

What volume is occupied by 2.719 x 1013 moles of methane gas, CH4?

slamgirl [31]

Answer:

6.5256×10¹⁴

Explanation:

n= v/24

v= n×25

v= 2.719×10¹³ × 24= 6.5256×10¹⁴ moles/dm³

hope it helps! please mark me brainliest

thank you! have a good day ahead

if u follow me, I will follow u back

7 0

3 years ago

Three metal spoons are on table. They are at room temperature. If the three spoons touch.

Alex

If the spoons touch, no heat will flow among the spoons because they are already in thermal equilibrium with each other. This is hinted by the statement "they are at room temperature" which means they all have the same temperature. Heat only flows when there is a difference in temperature.
The answer will be C. No heat will flow among the spoons

®PLEASE MARK AS BRAINLIEST TO HELP ME LEVEL UP®

5 0

3 years ago

Read 2 more answers

Chromium metal can be produced by the following reaction:

Mrac [35]

Answer:

17.3 g Cr

Explanation:

To find the mass of chromium, you need to (1) convert moles Si to moles Cr (using the mole-to-mole ratio from equation coefficients) and then (2) convert moles Cr to grams Cr (using the atomic mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (0.250).

3 Si + 2 Cr₂O₃ ---> 4 Cr + 3 SiO₂
^ ^

Atomic Mass (Cr): 51.996 g/mol

0.250 moles Si 4 moles Cr 51.996 g
------------------------- x -------------------- x ------------------- = 17.3 g Cr
3 moles Si 1 mole

6 0

2 years ago

The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way: OCl−+I−→OI−+Cl− T

motikmotik

Answer :

(a) The rate law for the reaction is:

$\text{Rate}=k[OCl^-]^1[I^-]^1$

(b) The value of rate constant is, $60.4M^{-1}s^{-1}$

(c) rate of the reaction is $6.52\times 10^{-5}Ms^{-1}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$OCl^-+I^-\rightarrow OI^-+Cl^-$

Rate law expression for the reaction:

$\text{Rate}=k[OCl^-]^a[I^-]^b$

where,

a = order with respect to $OCl^-$

b = order with respect to $I^-$

Expression for rate law for first observation:

$1.36\times 10^{-4}=k(1.5\times 10^{-3})^a(1.5\times 10^{-3})^b$ ....(1)

Expression for rate law for second observation:

$2.72\times 10^{-4}=k(3.0\times 10^{-3})^a(1.5\times 10^{-3})^b$ ....(2)

Expression for rate law for third observation:

$2.72\times 10^{-4}=k(1.5\times 10^{-3})^a(3.0\times 10^{-3})^b$ ....(3)

Dividing 1 from 2, we get:

$\frac{2.72\times 10^{-4}}{1.36\times 10^{-4}}=\frac{k(3.0\times 10^{-3})^a(1.5\times 10^{-3})^b}{k(1.5\times 10^{-3})^a(1.5\times 10^{-3})^b}\\\\2=2^a\\a=1$

Dividing 1 from 3, we get:

$\frac{2.72\times 10^{-4}}{1.36\times 10^{-4}}=\frac{k(1.5\times 10^{-3})^a(1.5\times 10^{-3})^b}{k(1.5\times 10^{-3})^a(3.0\times 10^{-3})^b}\\\\2=2^b\\b=1$

Thus, the rate law becomes:

$\text{Rate}=k[OCl^-]^a[I^-]^b$

a = 1 and b = 1

$\text{Rate}=k[OCl^-]^1[I^-]^1$

Now, calculating the value of 'k' (rate constant) by using any expression.

$1.36\times 10^{-4}=k(1.5\times 10^{-3})(1.5\times 10^{-3})$

$k=60.4M^{-1}s^{-1}$

Now we have to calculate the rate for a reaction when concentration of $OCl^-$ and $I^-$ is $1.8\times 10^{-3}M$ and $6.0\times 10^{-4}M$ respectively.