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Norma-Jean [14]
3 years ago
7

Primaries, the secret ballot, and the use of

Chemistry
1 answer:
algol [13]3 years ago
8 0
(4) Increase citizen participation in government

Primary: a way for citizens to vote for new government officials, not too influenced by party leaders
Secret Ballot: keeping a voter's votes private from others
Recall: a way for citizens to remove a government official from office
Referendum: a way for citizens to vote for or against something proposed by the legislature

During the Progressive Era, many local governments were lead by corrupt political machines. They would rig elections in their favor as well as threaten those who voted against them. Many would appoint their supporters who weren't usually qualified to government positions as incentive to vote for them (I don't know if you care but that's called the spoils system).

<span>It's not (1) because the whole point of primaries, secret ballots, recalls, and referendums was so political machines were not dominating
</span>It's not (2) because none of this has a lot to do with Native Americans
It's not (3) because the political machines were a <u>local</u> government problem, not federal
It <u><em></em>IS</u> (4) because by getting more people involved in the government, they can elect qualified officials, vote on laws that best benefit the people, and minimize corruption.
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Gas pressure is caused by
Rainbow [258]

Answer:

It's a rapid motion and collisions of molecules with the walls of the container that causes pressure.

7 0
3 years ago
Which statements about reducing sugars are true? D‑Glucose (an aldose) is a reducing sugar. The oxidation of a reducing sugar fo
qaws [65]

Answer:

The true statements are given below.

Explanation:

1 D glucose is a reducing sugar

2 The oxidation of reducing sugar forms a carboxylic acid sugar.

D glucose is a reducing sugar because glucose contain a free hydroxyl group (-OH)in its anomeric carbon.

 The oxidation of reducing sugar result in the conversion of -CHO group in case of aldose sugar and -CH2OH group in case of ketose sugar into carboxylic acid(-COOH).

4 0
3 years ago
Guys help me, please
Pepsi [2]

Answer:

radiation, conduction, convection, conduction

5 0
2 years ago
Read 2 more answers
write equations to show the chemical processes which occur when the first ionization and the second ionization energies of lithi
diamong [38]

Answer:

First ionization of lithium:

\text{Li}\;(g)\to \text{Li}^{+} \; (g) + \text{e}^{-}.

Second ionization of lithium:

\text{Li}^{+}\;(g) \to\text{Li}^{2+} \;(g) + \text{e}^{-}.

Explanation:

The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:

  • Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol (g) next to any atom or ion in the equation.
  • The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
  • Charge shall balance on the two sides of the equation.

First Ionization Energy of Li:

  • The products shall contain a gaseous ion with charge +1 \text{Li}^{+}\;(g) as well as an electron \text{e}^{-}.
  • Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: \text{Li}\;(g).
  • Hence the equation: \text{Li}\;(g) \to \text{Li}^{+}\;(g) + \text{e}^{-}.

Second Ionization Energy of Li:

  • The product shall contain a gaseous ion with charge +2: \text{Li}^{2+}\;(g) as well as an electron \text{e}^{-}.
  • Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?
  • The equation for this process is \text{Li}^{+} \; (g) \to \text{Li}^{2+}\;(g) + \text{e}^{-}.
5 0
3 years ago
Igneous rocks would most likely be found near:
geniusboy [140]

Answer:

the deep sea floor. Known as the oceanic crust.

Explanation:

The deep seafloor (the oceanic crust) is made almost entirely of basaltic rocks, with peridotite underneath in the mantle. Basalts are also erupted above the Earth's great subduction zones, either in volcanic island arcs or along the edges of continents.

Hope this helps :)

7 0
3 years ago
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