Using quadratic formula you can have a maximum of two solutions. When you set this problem equal to zero, your a=-1, b=-10, c=2
53 articles? Because josh wrote 13 plus 20 that Paulette wrote then Jeff wrote as many as Paulette so another 20.
Answer:
<h3> (x-8)²+(y-3)² = 81</h3>
Step-by-step explanation:
The general equation of a circle is expressed as;
(x-a)²+(y-b)² = r² where;
(a, b) is the centre of the circle
r is the radius
Given the centre (8, 3) and the radius of 9, the equation of the circle will be;
(x-a)²+(y-b)² = r²
(x-8)²+(y-3)² = 9²
(x-8)²+(y-3)² = 81
hence the required equation is (x-8)²+(y-3)² = 81
Answer:
Yes
Step-by-step explanation:
The fraction 4/5 is equivalent to 24/30 (To get this I multiplied both the numerator and denominator by 6). The fraction 5/6 is equivalent to 25/30 (To get this I multiplied both the numerator and denominator by 5).... Since 25 is greater than 24, 25/30 (or originally 5/6) is the larger fraction
A)
The question tells us that
y + z = 180
And
y=3x+20
z=x
So we put them in the first formula:
y + z = 180
(3x + 20) + x = 180
Add and get x to one side:
4x + 20 = 180
4x + 20 - 20 = 180-20
4x = 160
Divide both sides by 4
x = 40
B)
Put x back in to equation to get size of each angle:
Y =3x +20
Y=3(40)+20
Y=120+20
Y=140
Z=x
Z=40
Verify: y+z=180
140+40=180
180=180
