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Nonamiya [84]
3 years ago
12

A gas is compressed by an adiabatic process that decreases its volume by a factor of 2.

Physics
2 answers:
Rudiy273 years ago
7 0

Answer

OPTION A is correct

a)increases by a factor of more than 2.

Explanation:

adiabatic process is a process that takes place without the transfer of heat or mass between a thermodynamic system and its surroundings.

It is a process in which no heat transfer takes place. It does not denote that the temperature is constant.

Then from an adiabatic system,

we know that

PV= constant

PV^γ= constant

γ=ratio of specific heat for the gas

Where P= pressure of the system

V= volume of the system

We can say P= 1/(V^γ)

Where γ >1

Which means the pressure is inversely proportional to the volume raise to power of gamma sign and whenever the pressure increases the volume decreases with V^γ.

The question says the volume is decreased by factor of two then V^γ will also decreased by factor of 2.

That means (2^γ) > 2

Since our γ > 1 Therefore, the pressure increases by a factor of more than 2.

trasher [3.6K]3 years ago
5 0

Answer:

<em>a) increases by a factor of more than 2.</em>

Explanation:

In an adiabatic process,

PV^{Y} = constant

we can say that the volume is inverse to the pressure as

V^{Y}∝ \frac{1}{P}

where

P is the pressure

V is the volume

Y is the adiabatic index, and it is always greater than 1

If volume V is decreased by a factor of 2, then it is actually decreased by a factor of 2^{Y} in proportion to the pressure, and since Y is always greater than 1, it is actually decreased by a factor greater than 2 in proportion to the pressure.

This means that the pressure will also increase by a factor greater than 2.

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