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3 years ago

Watch as the coefficients are being

Physics

1 answer:

Nutka1998 [239]3 years ago

7 0

Yes, because its correct and if yu just look it up you can get it. lol your welcome

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which of the following is a benefit associated with nuclear energy(a)radioisotope used as tracers in industry(b)radiophosphorous

Lelechka [254]

There are multiple uses of nuclear energy, one of which is these uses is (A) radioisotope used as tracers in industry<span>. A radioactive isotope is injected into the patient's area of interest, for example the bowel, and the movement of the radioactive isotope is tracked using the radiation it emits.</span>

7 0

3 years ago

The specific heat of water in its solid phase (ice) is 2090 J/(kg K), while in the liquid phase (water) its specific heat is 419

oee [108]

Answer:

d. 149 ⁰C.

Explanation:

Given;

mass of the block of ice, m = 2 kg

specific heat capacity of the ice, C = 2090 J/(kgK)

initial temperature of the ice, t₁ = -90 ⁰C

heat added to the ice, H = 1,000,000 J

let the final temperature of the ice = t₂

The final temperature of the ice after adding the heat is calculated as follows;

$H = mC_{ice} \Delta t\\\\H = mC_{ice} (t_2 - t_1)\\\\1,000,000 = 2 \times 2090 \times (t_2 - (-90))\\\\1,000,000 = 4,180(t_2 +90)\\\\1,000,000 = 4,180t_2 + 376,200\\\\1,000,000 - 376,200 = 4,180t_2\\\\623,800 = 4,180 t_2\\\\t_2 = \frac{623,800}{4,180} \\\\t_2 = 149 \ ^0C$

Therefore, the new temperature of the water is 149 ⁰C.

4 0

3 years ago

If he completes the 200 m dash in 23 s and runs at constant speed throughout the race, what is his centripetal acceleration as h

Blababa [14]

Incomplete question.The complete one is here

A runner taking part in the 200m dash must run around the end of a track that has a circular arc with a radius curvature of 30m. The runner starts the race at a constant speed. If she completes the 200m dash in 23s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track?

Answer:

$a_c=2.523m/s^2$

Explanation:

Given data

$L_{length}=200m\\r_{radius}=30m\\t_{time}=23s$

Required

Centripetal acceleration

Solution

According to the motions equation the velocity given by:

$V_{velocity}=\frac{L_{length}}{t_{time}}\\V_{velocity}=\frac{200m}{23s}\\V_{velocity}=8.7m/s$

The centripetal acceleration is given by:

$a_{c}=\frac{V_{velocity}^2}{r_{radius}}\\ a_c=\frac{(8.7m/s)^2}{30m}\\ a_c=2.523m/s^2$

4 0

4 years ago

An object on Earth's surface has a weight of 609 N. What is its mass?

mars1129 [50]

Answer:

62.1 kg

Explanation:

Weight = mass × acceleration

609 N = mass × (9.8)

The acceleration is 9.8 because that is the acceleration of gravity.

Divide both sides by 9.8 to isolate the mass.

609N/9.8 = mass

62.1 kg =mass

6 0

4 years ago

If a velocity is positive which would most likely yield a negative acceleration

Aleksandr [31]

Answer:

A time that is less than half an hour

Explanation:

it says velocity is positive so it would yield to a negative acceleration

5 0

3 years ago