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3 years ago

Based on the diagram of a ball rolling down hill, what statement is true?

Physics

1 answer:

melisa1 [442]3 years ago

7 0

Answer:

D) The ball in box C has less potential energy than the ball in box B.

Explanation:

potential energy is directly proportional to height. A higher ball will have higher gravity potential energy.

A) The ball in box C has MORE kinetic energy than the ball in box B. It is lower so mort potential energy has been converted to kinetic energy.

B) The ball in box A has LESS kinetic energy than the ball in box B. It is higher at A so Less potential energy has been converted to kinetic

C) The ball in box C has LESS potential energy than the ball in box B. it is lower

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During which of the following chemical changes does C02 bubbles form?

sweet [91]

Answer:

Carbon dioxide is formed when sodium carbonate or sodium hydrogen carbonate is reacted with any mineral acid or organic acid

Explanation:

$.$

7 0

3 years ago

You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has what energy, kineti

mihalych1998 [28]

Both kinetic and potential. Kinetic as it is moving and Potential due to its relative position to the ground, in this case it is in the air, elevated from the ground.

4 0

3 years ago

The distance covered by a car at a time, t is given by x = 20t + 6t4, calculate

Anni [7]

Answer:

(i) v = 44 m/s

(ii) a = 72 m/s^2

Explanation:

You have the following equation for the potion of a car:

$x=20t+6t^4$

(i) The instantaneous velocity is the derivative of x in time:

$\frac{dx}{dt}=20+(6)(4)t^3=20+24t^3$

for t = 1 is:

$v(t=1)=\frac{dx}{dt}=20+24(1)^3=44m/s$

(ii) The instantaneous acceleration is the derivative of the velocity:

$\frac{dv}{dt}=24(3)t^2=72t^2$

for t = 1

$a(t=1)=\frac{dv}{dt}=72(1)^2=72m/s^2$

8 0

3 years ago

a nonrelativistic proton is confined to a length of 2.0 pm on the x-axis. what is the kinetic energy of the proton if its speed

Elina [12.6K]

Answer:

K = 1.29eV

Explanation:

In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:

$\Delta x \Delta p\geq \frac{h}{4\pi}$ (1)

Δx : uncertainty of position = 2.0pm = 2.0*10^-12m

Δp: uncertainty of momentum = ?

h: Planck's constant = 6.626*10^-34 J.s

You calculate the minimum possible value of Δp from the equation (1):

$\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}$

The minimum kinetic energy is calculated by using the following formula:

$k=\frac{(\Delta p)^2}{2m}$ (2)

m: mass of the proton = 1.67*10^{-27}kg

$k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J$

in eV you have:

$2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV$

The kinetic energy of the proton is 1.29eV

7 0

3 years ago

What is the force on an object with a mass of 25 kg and an acceleration of 5 m/s/s? 1 point

Oduvanchick [21]

Answer:125N

Explanation:

Mass =25kg

Acceleration =5m/s/s

Force=mass x acceleration

Force=25 x 5

Force=125N

7 0

3 years ago